Lære Void Return Type | Function Return Values Specification

The void return type indicates that a function does not return a value. Such a function performs its task but doesn’t produce a result to be used elsewhere in the program. For example, consider a function that prints the values of a 1D dynamic array.

main.cpp


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#include <iostream>

// Function to print values of a 1D dynamic array
void print_array(const int* arr, const int size)
{
    for (int i = 0; i < size; ++i)
        std::cout << arr[i] << " ";
    
    std::cout << std::endl;
}

int main() 
{
    // Example 1D dynamic array
    int size = 5;
    int* dynamic_array = new int[size] { 1, 2, 3, 4, 5 };

    // Call the function to print the array values
    print_array(dynamic_array, size);

    // Deallocate the dynamically allocated memory
    delete[] dynamic_array;
}

The purpose of this function is to print the array, and it doesn’t return any meaningful result, so a void return type is appropriate. However, you can still use the return statement in a void function to end its execution early under certain conditions.

main.cpp


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#include <iostream>

void display_division(double a, double b)
{
    if (b == 0) 
        return;
    
    std::cout << "displayDivision was called: " << a / b << std::endl;
}

int main() 
{
    // Call the function to print the division result
    display_division(15, 8);
    
    // Now second argument is zero
    display_division(15, 0);
}

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main.cpp


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#include <iostream>

// Function to print values of a 1D dynamic array
void print_array(const int* arr, const int size)
{
    for (int i = 0; i < size; ++i)
        std::cout << arr[i] << " ";
    
    std::cout << std::endl;
}

int main() 
{
    // Example 1D dynamic array
    int size = 5;
    int* dynamic_array = new int[size] { 1, 2, 3, 4, 5 };

    // Call the function to print the array values
    print_array(dynamic_array, size);

    // Deallocate the dynamically allocated memory
    delete[] dynamic_array;
}

main.cpp


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#include <iostream>

void display_division(double a, double b)
{
    if (b == 0) 
        return;
    
    std::cout << "displayDivision was called: " << a / b << std::endl;
}

int main() 
{
    // Call the function to print the division result
    display_division(15, 8);
    
    // Now second argument is zero
    display_division(15, 0);
}

Var alt klart?

Tak for dine kommentarer!

Sektion 3. Kapitel 4