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Lære Insertion Sort | Simple Algorithms
Sorting Algorithms
course content

Kursusindhold

Sorting Algorithms

Sorting Algorithms

1. Simple Algorithms
2. Divide and Conquer Algorithms
3. Problems

book
Insertion Sort

Insertion Sort is another simple sort algorithm that works with sorted and unsorted parts of an array. Values from unsorted part picked and placed to correct position in sorted part.

Example1

Example 2

[4 | 3 2 10 12 1 4 6] -> [3 4 | 2 10 12 1 4 6]

[3 4 | 2 10 12 1 4 6] -> [2 3 4 | 10 12 1 4 6]

[2 3 4 | 10 12 1 4 6]-> [2 3 4 10 | 12 1 4 6]

[2 3 4 10 | 12 1 4 6] -> [2 3 4 10 12 | 1 4 6]

[2 3 4 10 12 | 1 4 6] -> [1 2 3 4 10 12 | 4 6]

[1 2 3 4 10 12 | 4 6] -> [1 2 3 4 4 10 12 | 6]

[1 2 3 4 4 10 12 | 6] -> [1 2 3 4 4 6 10 12]

Time complexity is O(N^2), because each next element of an unsorted part iterates through elements of the sorted part. There are two nested loops in the algorithm.

Space complexity: O(1).

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def insertionSort(arr): # Iterate unsorted subarrays for i in range(1, len(arr)): key = arr[i] # Element to move j = i-1 # Iterate sorted part and replace elements one position right while j>=0 and key < arr[j]: arr[j+1] = arr[j] j-=1 # Put key element on its position arr[j+1]= key return arr
copy
Opgave

Swipe to start coding

Use the insertionSort() function to sort an array. You can either use the existing function or implement it yourself. Output the sorted array.

Løsning

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Sektion 1. Kapitel 4
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book
Insertion Sort

Insertion Sort is another simple sort algorithm that works with sorted and unsorted parts of an array. Values from unsorted part picked and placed to correct position in sorted part.

Example1

Example 2

[4 | 3 2 10 12 1 4 6] -> [3 4 | 2 10 12 1 4 6]

[3 4 | 2 10 12 1 4 6] -> [2 3 4 | 10 12 1 4 6]

[2 3 4 | 10 12 1 4 6]-> [2 3 4 10 | 12 1 4 6]

[2 3 4 10 | 12 1 4 6] -> [2 3 4 10 12 | 1 4 6]

[2 3 4 10 12 | 1 4 6] -> [1 2 3 4 10 12 | 4 6]

[1 2 3 4 10 12 | 4 6] -> [1 2 3 4 4 10 12 | 6]

[1 2 3 4 4 10 12 | 6] -> [1 2 3 4 4 6 10 12]

Time complexity is O(N^2), because each next element of an unsorted part iterates through elements of the sorted part. There are two nested loops in the algorithm.

Space complexity: O(1).

123456789101112131415
def insertionSort(arr): # Iterate unsorted subarrays for i in range(1, len(arr)): key = arr[i] # Element to move j = i-1 # Iterate sorted part and replace elements one position right while j>=0 and key < arr[j]: arr[j+1] = arr[j] j-=1 # Put key element on its position arr[j+1]= key return arr
copy
Opgave

Swipe to start coding

Use the insertionSort() function to sort an array. You can either use the existing function or implement it yourself. Output the sorted array.

Løsning

Switch to desktopSkift til skrivebord for at øve i den virkelige verdenFortsæt der, hvor du er, med en af nedenstående muligheder
Var alt klart?

Hvordan kan vi forbedre det?

Tak for dine kommentarer!

Sektion 1. Kapitel 4
Switch to desktopSkift til skrivebord for at øve i den virkelige verdenFortsæt der, hvor du er, med en af nedenstående muligheder
Vi beklager, at noget gik galt. Hvad skete der?
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