Challenge
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Aufgabe
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Your code accepts the sentence from the user. You should define if it is short, medium, or large.
- Accept the text message from the user as input and store it in the variable
sentence. - Using the statement
ifand functionlength()we check if our statement is large. If the sentence’s length is greater than30, we print the message"The sentence is large!". - Using the statement
else ifand functionlength()we check if our statement is medium. If the sentence’s length is greater than10(but less than30), we print the message `"The sentence is medium!". - Using the statement
elseand functionlength()we check if our statement is short. If the sentence’s length is less than10, we print the message"The sentence is medium!".
Please, don’t forget to type the semicolon at the end of the lines.
Lösung
#include <iostream>
using namespace std;
int main() {
// Declare variables
string sentence;
// User input
cout << "Type the sentence: ";
cin >> sentence;
// Check the length
if (sentence.length() > 30) {
cout << "The sentence is large!";
} else if (sentence.length() > 10) {
cout << "The sentence is medium!";
} else {
cout << "The sentence is short!";
}
}
War alles klar?
Danke für Ihr Feedback!
Abschnitt 3. Kapitel 7
#include <iostream>
using namespace std;
int main() {
// Declare variables
string sentence
// User input
cout << "Type the sentence: ";
_ _ _
// Check the length
_ _ _
_ _ _
_ _ _
_ _ _
_ _ _
_ _ _
_ _ _
}
