Lernen Challenge: Attendance Summary Report

In your HR automation journey so far, you have explored how to work with lists of employee data and how to automate simple attendance tasks. Comparing lists is a fundamental skill: you often need to determine which employees are present, absent, or require follow-up. When generating reports, this typically means cross-referencing a master list (such as all employee IDs) against a list of those who have checked in or been marked present on a given day. Automating this process saves time and reduces errors, ensuring your attendance records are always up to date.


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all_employee_ids = ["E101", "E102", "E103", "E104", "E105"]
present_today = ["E101", "E104", "E105"]

for emp_id in all_employee_ids:
    if emp_id in present_today:
        print(emp_id, "is present")
    else:
        print(emp_id, "is absent")

When formatting your attendance summary, clarity is key. Consider grouping present and absent employees into separate lists or sections, and use clear headings like Present Employees and Absent Employees. This makes it easy for managers or HR staff to quickly review attendance status and take any necessary action. Using consistent spacing and line breaks between sections also improves readability.

Aufgabe

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Write a script that prints two lists: one of present employees and one of absent employees, based on the provided data.

Create a list of present employees by checking which IDs from all_employee_ids are in present_today.
Create a list of absent employees by checking which IDs from all_employee_ids are not in present_today.
Print a header "Present Employees:" followed by the list of present employees.
Print a header "Absent Employees:" followed by the list of absent employees.

Lösung

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Abschnitt 1. Kapitel 7

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Suggested prompts:

Can you show me how to group present and absent employees into separate lists?

How can I format the attendance summary with clear headings?

What are some best practices for making attendance reports more readable?

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              12345678
            
all_employee_ids = ["E101", "E102", "E103", "E104", "E105"]
present_today = ["E101", "E104", "E105"]

for emp_id in all_employee_ids:
    if emp_id in present_today:
        print(emp_id, "is present")
    else:
        print(emp_id, "is absent")