Contenido del Curso

C++ Data Types

1. Introduction

Overview Arithmetic Operations Division int and double Math in C++Specifying a Type

2. Numerical Data Types

Integers Using Integers Type modifier Float Double Numerical Data Types Summary

3. Text Data Type

Char String Indexing a String Working With String Changing The String Practice Finding Text in a String Strings in Memory

4. Other Data Types and Concepts

Boolean Boolean Expressions Void Auto Unsigned Implicit Type Conversion Explicit Type Conversion

Indexing a String

We can access the elements of a string (which are chars) using indexing with square brackets [] just like we would do with an array. Using that, we can also replace a character at a given position.

With that indexing, you can try to access a wrong index (that is out of range), and the compiler will tell you nothing about that.

main


              1234567
            
#include <iostream>

int main()
{
    std::string word = "Codefinity";
    std::cout << word[12]; // Word's length is 10
}

As you can see, the output is weird, and C++ did not warn you about the problem (as always...). To avoid it, you can get the length of a string using the .length() method and ensure your index is smaller than the length of your string.

main


              123456789101112
            
#include <iostream>

int main()
{
    std::string word = "Codefinity";
    int index = 12;
    
    if (index >= word.length()) 
	    std::cout << "The output is unexpected!" << std::endl;
    else
        std::cout << word[index]; // Word's length is 10
}

Another way of indexing is using the .at() method. To get the character with index n, we can use the following syntax:

It works the same as str[n] but will raise an error if you specify an index that is out of range.

main


              123456789
            
#include <iostream>
using namespace std;

int main()
{
  string word = "Codefinity";
  cout << word.at(12); // word's length is 10
  return 0;
}

Try outputting the character with the index 5 in the code window above.

Let's sum up what we used in this chapter:

Practice

As was said before, we can replace the characters inside a string using indexing (both with [] and .at()). Here is an example:

main


              1234567891011
            
#include <iostream>
using namespace std;

int main()
{
  string word = "Cpdefinitu";
  word[1] = 'o';
  word.at(word.length()-1) = 'y'; // length-1 accesses the last element
  cout << word;
  return 0;
}

Tarea

Your task is to check if we can add characters to the end of a string that way.

Figure the index of the last character in a string.
Assign 'y' to the index index of last character + 1 of str.

Cambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones

¿Todo estuvo claro?

¡Gracias por tus comentarios!

Sección 3. Capítulo 3

Indexing a String

With that indexing, you can try to access a wrong index (that is out of range), and the compiler will tell you nothing about that.

main


              1234567
            
#include <iostream>

int main()
{
    std::string word = "Codefinity";
    std::cout << word[12]; // Word's length is 10
}

main


              123456789101112
            
#include <iostream>

int main()
{
    std::string word = "Codefinity";
    int index = 12;
    
    if (index >= word.length()) 
	    std::cout << "The output is unexpected!" << std::endl;
    else
        std::cout << word[index]; // Word's length is 10
}

Another way of indexing is using the .at() method. To get the character with index n, we can use the following syntax:

It works the same as str[n] but will raise an error if you specify an index that is out of range.

main


              123456789
            
#include <iostream>
using namespace std;

int main()
{
  string word = "Codefinity";
  cout << word.at(12); // word's length is 10
  return 0;
}

Try outputting the character with the index 5 in the code window above.

Let's sum up what we used in this chapter:

Practice

As was said before, we can replace the characters inside a string using indexing (both with [] and .at()). Here is an example:

main


              1234567891011
            
#include <iostream>
using namespace std;

int main()
{
  string word = "Cpdefinitu";
  word[1] = 'o';
  word.at(word.length()-1) = 'y'; // length-1 accesses the last element
  cout << word;
  return 0;
}

Tarea

Your task is to check if we can add characters to the end of a string that way.

Figure the index of the last character in a string.
Assign 'y' to the index index of last character + 1 of str.

Cambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones

¿Todo estuvo claro?

¡Gracias por tus comentarios!

Sección 3. Capítulo 3

Indexing a String

With that indexing, you can try to access a wrong index (that is out of range), and the compiler will tell you nothing about that.

main


              1234567
            
#include <iostream>

int main()
{
    std::string word = "Codefinity";
    std::cout << word[12]; // Word's length is 10
}

main


              123456789101112
            
#include <iostream>

int main()
{
    std::string word = "Codefinity";
    int index = 12;
    
    if (index >= word.length()) 
	    std::cout << "The output is unexpected!" << std::endl;
    else
        std::cout << word[index]; // Word's length is 10
}

Another way of indexing is using the .at() method. To get the character with index n, we can use the following syntax:

It works the same as str[n] but will raise an error if you specify an index that is out of range.

main


              123456789
            
#include <iostream>
using namespace std;

int main()
{
  string word = "Codefinity";
  cout << word.at(12); // word's length is 10
  return 0;
}

Try outputting the character with the index 5 in the code window above.

Let's sum up what we used in this chapter:

Practice

As was said before, we can replace the characters inside a string using indexing (both with [] and .at()). Here is an example:

main


              1234567891011
            
#include <iostream>
using namespace std;

int main()
{
  string word = "Cpdefinitu";
  word[1] = 'o';
  word.at(word.length()-1) = 'y'; // length-1 accesses the last element
  cout << word;
  return 0;
}

Tarea

Your task is to check if we can add characters to the end of a string that way.

Figure the index of the last character in a string.
Assign 'y' to the index index of last character + 1 of str.

Cambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones

¿Todo estuvo claro?

¡Gracias por tus comentarios!

With that indexing, you can try to access a wrong index (that is out of range), and the compiler will tell you nothing about that.

main


              1234567
            
#include <iostream>

int main()
{
    std::string word = "Codefinity";
    std::cout << word[12]; // Word's length is 10
}

main


              123456789101112
            
#include <iostream>

int main()
{
    std::string word = "Codefinity";
    int index = 12;
    
    if (index >= word.length()) 
	    std::cout << "The output is unexpected!" << std::endl;
    else
        std::cout << word[index]; // Word's length is 10
}

Another way of indexing is using the .at() method. To get the character with index n, we can use the following syntax:

It works the same as str[n] but will raise an error if you specify an index that is out of range.

main


              123456789
            
#include <iostream>
using namespace std;

int main()
{
  string word = "Codefinity";
  cout << word.at(12); // word's length is 10
  return 0;
}

Try outputting the character with the index 5 in the code window above.

Let's sum up what we used in this chapter:

Practice

As was said before, we can replace the characters inside a string using indexing (both with [] and .at()). Here is an example:

main


              1234567891011
            
#include <iostream>
using namespace std;

int main()
{
  string word = "Cpdefinitu";
  word[1] = 'o';
  word.at(word.length()-1) = 'y'; // length-1 accesses the last element
  cout << word;
  return 0;
}

Tarea

Your task is to check if we can add characters to the end of a string that way.

Figure the index of the last character in a string.
Assign 'y' to the index index of last character + 1 of str.

Cambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones

Sección 3. Capítulo 3

Cambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones