Oppiskele Void | Pointers

We've previously encountered void when we looked at functions that don't return anything or just display text on the screen.

Keep in mind that we can't declare a variable of the void type. However, we can create a void* pointer that points to a memory location.

Note

If you've worked through the pointer exercises in the section, you'll know that all pointers occupy 8 bytes. A void* pointer is no different.

A void* pointer isn't tied to any specific data type. This flexibility allows us to store the address of any data type in it.

However, there's a catch: we can't dereference a void* pointer.

Note

This limitation stems from the same reason we can't declare variables of the void type.

Perform an explicit type conversion!

Main.c


              123456789101112131415161718192021
            
#include <stdio.h>

int main()
{
    char c = 'F';
    int i = 100;
    double d = 3.15;

    void* pV;

    pV = &c;
    printf("%c \n", *((char*)pV));

    pV = &i;
    printf("%d \n", *((int*)pV));

    pV = &d;
    printf("%.2f \n", *((double*)pV));

    return 0;
}

Congratulations on completing the basic course in C programming! If you're eager to dive deeper into this fascinating and logical programming language, I highly recommend delving into topics like macros, sorting algorithms, and data structures. Additionally, familiarizing yourself with one of the Linux distributions is invaluable for any seasoned C programmer.

Best of luck!

Oliko kaikki selvää?

Kiitos palautteestasi!

Osio 6. Luku 6

Kysy tekoälyä

Kysy mitä tahansa tai kokeile jotakin ehdotetuista kysymyksistä aloittaaksesi keskustelumme

Pyyhkäise näyttääksesi valikon

We've previously encountered void when we looked at functions that don't return anything or just display text on the screen.

Keep in mind that we can't declare a variable of the void type. However, we can create a void* pointer that points to a memory location.

Note

If you've worked through the pointer exercises in the section, you'll know that all pointers occupy 8 bytes. A void* pointer is no different.

A void* pointer isn't tied to any specific data type. This flexibility allows us to store the address of any data type in it.

However, there's a catch: we can't dereference a void* pointer.

Note

This limitation stems from the same reason we can't declare variables of the void type.

Perform an explicit type conversion!

Main.c


              123456789101112131415161718192021
            
#include <stdio.h>

int main()
{
    char c = 'F';
    int i = 100;
    double d = 3.15;

    void* pV;

    pV = &c;
    printf("%c \n", *((char*)pV));

    pV = &i;
    printf("%d \n", *((int*)pV));

    pV = &d;
    printf("%.2f \n", *((double*)pV));

    return 0;
}

Best of luck!

Oliko kaikki selvää?

Kiitos palautteestasi!

Osio 6. Luku 6

Void

Perform an explicit type conversion!

Awesome!

Void

Perform an explicit type conversion!