Void Return Type
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The void return type indicates that a function does not return a value.
Such a function performs its task but doesn’t produce a result to be used elsewhere in the program. For example, consider a function that prints the values of a 1D dynamic array.
main.cpp
1234567891011121314151617181920212223#include <iostream> // Function to print values of a 1D dynamic array void print_array(const int* arr, const int size) { for (int i = 0; i < size; ++i) std::cout << arr[i] << " "; std::cout << std::endl; } int main() { // Example 1D dynamic array int size = 5; int* dynamic_array = new int[size] { 1, 2, 3, 4, 5 }; // Call the function to print the array values print_array(dynamic_array, size); // Deallocate the dynamically allocated memory delete[] dynamic_array; }
The purpose of this function is to print the array, and it doesn’t return any meaningful result, so a void return type is appropriate. However, you can still use the return statement in a void function to end its execution early under certain conditions.
main.cpp
123456789101112131415161718#include <iostream> void display_division(double a, double b) { if (b == 0) return; std::cout << "displayDivision was called: " << a / b << std::endl; } int main() { // Call the function to print the division result display_division(15, 8); // Now second argument is zero display_division(15, 0); }
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