Challenge: Replace Outliers with Median
Outliers can significantly impact the quality of your data analysis, especially when they arise from errors or rare events that do not reflect typical patterns. When you want to reduce the influence of extreme values while keeping all your data points, replacing outliers with the median of the column is a robust technique. The median is resistant to the effect of outliers, so it provides a stable replacement value that maintains the overall distribution of your data. This approach is especially useful when you want to avoid losing data by removing rows, and when the mean would be skewed by the very outliers you are trying to address.
123456789101112131415161718import pandas as pd # Example DataFrame with outliers in the 'score' column data = { "name": ["Alice", "Bob", "Charlie", "David", "Eve"], "score": [85, 90, 300, 88, 92] # 300 is an outlier } df = pd.DataFrame(data) # Let's say outliers have been identified using the IQR method # For this example, we know that 300 is an outlier outlier_mask = df["score"] > 150 print("Original DataFrame:") print(df) print("\nOutlier mask:") print(outlier_mask)
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Write a function that replaces outlier values in a specified column of a DataFrame with the median value of that column. Use a boolean mask to identify which values are outliers. The function must update the DataFrame in place so that all outlier values in the specified column are replaced with the column's median.
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Outliers can significantly impact the quality of your data analysis, especially when they arise from errors or rare events that do not reflect typical patterns. When you want to reduce the influence of extreme values while keeping all your data points, replacing outliers with the median of the column is a robust technique. The median is resistant to the effect of outliers, so it provides a stable replacement value that maintains the overall distribution of your data. This approach is especially useful when you want to avoid losing data by removing rows, and when the mean would be skewed by the very outliers you are trying to address.
123456789101112131415161718import pandas as pd # Example DataFrame with outliers in the 'score' column data = { "name": ["Alice", "Bob", "Charlie", "David", "Eve"], "score": [85, 90, 300, 88, 92] # 300 is an outlier } df = pd.DataFrame(data) # Let's say outliers have been identified using the IQR method # For this example, we know that 300 is an outlier outlier_mask = df["score"] > 150 print("Original DataFrame:") print(df) print("\nOutlier mask:") print(outlier_mask)
Swipe to start coding
Write a function that replaces outlier values in a specified column of a DataFrame with the median value of that column. Use a boolean mask to identify which values are outliers. The function must update the DataFrame in place so that all outlier values in the specified column are replaced with the column's median.
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