Challenge: Finding the Top 3 Hardest-Working Employees
Tehtävä
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Several employees work at the factory, and we need to identify the three hardest-working employees based on the number of hours worked.
- Sort the list of
workersin ascending order by the number ofhoursWorkedusing thecomparingInt()method. - Reverse the list of
workersto make it descending by the number ofhoursWorkedusing thereversed()method. - Select the top three workers with the highest
hoursWorkedusing thelimit()method. - Print each of these three workers to the console.
Ratkaisu
solution.java
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package com.example;
import java.util.List;
import java.util.Comparator;
public class Main {
public static void main(String[] args) {
List<Worker> workers = List.of(
new Worker("John", 160),
new Worker("Michael", 200),
new Worker("Andrew", 180),
new Worker("David", 220),
new Worker("Robert", 175)
);
List<Worker> topWorkers = workers.stream()
.sorted(Comparator.comparingInt(Worker::getHoursWorked).reversed())
.limit(3)
.toList();
topWorkers.forEach(System.out::println);
}
}
class Worker {
private String name;
private int hoursWorked;
public Worker(String name, int hoursWorked) {
this.name = name;
this.hoursWorked = hoursWorked;
}
public String getName() {
return name;
}
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Osio 2. Luku 10
single
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package com.example;
import java.util.List;
import java.util.Comparator;
public class Main {
public static void main(String[] args) {
List<Worker> workers = List.of(
new Worker("John", 160),
new Worker("Michael", 200),
new Worker("Andrew", 180),
new Worker("David", 220),
new Worker("Robert", 175)
);
List<Worker> topWorkers = workers.stream()
.sorted(Comparator.comparingInt(___).___)
.___
.toList();
topWorkers.forEach(___);
}
}
class Worker {
private String name;
private int hoursWorked;
public Worker(String name, int hoursWorked) {
this.name = name;
this.hoursWorked = hoursWorked;
}
public String getName() {
return name;
}
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