Chaining Multiple Decorators
1234567891011121314151617def bold_decorator(func): def wrapper(*args, **kwargs): return "<b>" + func(*args, **kwargs) + "</b>" return wrapper def italic_decorator(func): def wrapper(*args, **kwargs): return "<i>" + func(*args, **kwargs) + "</i>" return wrapper @bold_decorator @italic_decorator def greet(): return "Hello!" print(greet()) # Output: <b><i>Hello!</i></b>
When you chain multiple decorators on a single function, Python applies them from the closest decorator to the function outward, but executes them in the reverse order. In the provided example, @italic_decorator is applied to greet first, then @bold_decorator wraps the result. This means that when you call greet(), the call first goes through bold_decorator, which then calls the version of greet that has already been wrapped by italic_decorator. As a result, the output is enclosed first in <i>...</i>, then in <b>...</b>, producing <b><i>Hello!</i></b>. Understanding this order is crucial when combining multiple decorators, as the sequence can affect the final behavior and output of your function.
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Can you explain what would happen if I reversed the order of the decorators?
How do decorators work with functions that take arguments?
Can you show an example with more than two decorators?
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Completion rate improved to 5.88Chaining Multiple Decorators
Pyyhkäise näyttääksesi valikon
1234567891011121314151617def bold_decorator(func): def wrapper(*args, **kwargs): return "<b>" + func(*args, **kwargs) + "</b>" return wrapper def italic_decorator(func): def wrapper(*args, **kwargs): return "<i>" + func(*args, **kwargs) + "</i>" return wrapper @bold_decorator @italic_decorator def greet(): return "Hello!" print(greet()) # Output: <b><i>Hello!</i></b>
When you chain multiple decorators on a single function, Python applies them from the closest decorator to the function outward, but executes them in the reverse order. In the provided example, @italic_decorator is applied to greet first, then @bold_decorator wraps the result. This means that when you call greet(), the call first goes through bold_decorator, which then calls the version of greet that has already been wrapped by italic_decorator. As a result, the output is enclosed first in <i>...</i>, then in <b>...</b>, producing <b><i>Hello!</i></b>. Understanding this order is crucial when combining multiple decorators, as the sequence can affect the final behavior and output of your function.
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