Notice: This page requires JavaScript to function properly.
Please enable JavaScript in your browser settings or update your browser.
Apprendre Challenge: ODE Solver Accuracy and Stability | Differential Equations and Dynamic Systems
Numerical Methods for Scientific Computing with Python

bookChallenge: ODE Solver Accuracy and Stability

You will implement and compare two numerical ODE solvers for the initial value problem (IVP):

dydt=f(t,y),y(t0)=y0\frac{dy}{dt} = f(t, y), \qquad y(t_0)=y_0

You will implement:

Euler Method

  • First-order method (less accurate).
  • Can become unstable for stiff or sensitive problems.

Runge–Kutta 4 (RK4)

  • Fourth-order method (more accurate).
  • Typically more stable than Euler for the same step size.

You will solve the test ODE:

dydt=y,y(0)=1\frac{dy}{dt} = y,\quad y(0)=1

The analytical solution is:

y(t)=ety(t)=e^t
Tâche

Swipe to start coding

  • Implement euler_solver and rk4_solver.
  • Use a fixed step size h and integrate from t0 to t_end.
  • Return the final value (y(tend)y(t_{end})).
  • Compute the absolute error compared to (etende^{t_{end}}).

Solution

Tout était clair ?

Comment pouvons-nous l'améliorer ?

Merci pour vos commentaires !

Section 3. Chapitre 4
single

single

Demandez à l'IA

expand

Demandez à l'IA

ChatGPT

Posez n'importe quelle question ou essayez l'une des questions suggérées pour commencer notre discussion

Suggested prompts:

Can you show me how to implement the Euler method for this ODE?

Can you explain how the RK4 method works for this problem?

How do the numerical solutions compare to the analytical solution?

close

bookChallenge: ODE Solver Accuracy and Stability

Glissez pour afficher le menu

You will implement and compare two numerical ODE solvers for the initial value problem (IVP):

dydt=f(t,y),y(t0)=y0\frac{dy}{dt} = f(t, y), \qquad y(t_0)=y_0

You will implement:

Euler Method

  • First-order method (less accurate).
  • Can become unstable for stiff or sensitive problems.

Runge–Kutta 4 (RK4)

  • Fourth-order method (more accurate).
  • Typically more stable than Euler for the same step size.

You will solve the test ODE:

dydt=y,y(0)=1\frac{dy}{dt} = y,\quad y(0)=1

The analytical solution is:

y(t)=ety(t)=e^t
Tâche

Swipe to start coding

  • Implement euler_solver and rk4_solver.
  • Use a fixed step size h and integrate from t0 to t_end.
  • Return the final value (y(tend)y(t_{end})).
  • Compute the absolute error compared to (etende^{t_{end}}).

Solution

Switch to desktopPassez à un bureau pour une pratique réelleContinuez d'où vous êtes en utilisant l'une des options ci-dessous
Tout était clair ?

Comment pouvons-nous l'améliorer ?

Merci pour vos commentaires !

Section 3. Chapitre 4
single

single

some-alt