You have explored how to apply **Kirchhoff's Voltage Law (KVL)** to basic and moderately complex circuits, and learned to set up and solve the resulting equations using Python's linear algebra tools. In this challenge, you will use these skills to analyze a two-loop circuit with three resistors and two voltage sources. Recall that **KVL** states the sum of voltage drops and rises around any closed loop is zero, allowing you to translate circuit diagrams into systems of equations. Python's `scipy.linalg` library provides efficient methods for solving such systems, making it a powerful tool for electrical circuit analysis.


import unittest
import user_code
import ast
import re   
import importlib
import csv
import unittest
import importlib
import numpy as np

class TestTask(unittest.TestCase):
    def test_returns_correct_currents_for_sample(self):
        import user_code
        importlib.reload(user_code)
        result = user_code.solve_multi_loop_circuit(100, 150, 220, 10, 5)
        _dynamic_test(
            self,
            result is not None and isinstance(result, tuple) and len(result) == 2,
            "Function returns a tuple of two values for sample input.",
            f"Expected a tuple of two current values, got: {result}",
        )
        # Calculate expected currents using the same method
        A = np.array([[250, -150], [-150, 370]])
        b = np.array([10, 5])
        expected = np.linalg.solve(A, b)
        I1_exp, I2_exp = expected[0], expected[1]
        _dynamic_test(
            self,
            np.isclose(result[0], I1_exp, atol=1e-6) and np.isclose(result[1], I2_exp, atol=1e-6),
            f"Returns correct currents for (100, 150, 220, 10, 5)",
            f"Expected currents ({I1_exp}, {I2_exp}), got {result}",
        )

    def test_arbitrary_positive_values(self):
        import user_code
        importlib.reload(user_code)
        # Arbitrary positive values
        R1, R2, R3, V1, V2 = 50, 40, 60, 20, 10
        result = user_code.solve_multi_loop_circuit(R1, R2, R3, V1, V2)
        _dynamic_test(
            self,
            result is not None and isinstance(result, tuple) and len(result) == 2,
            "Function returns a tuple of two values for arbitrary positive input.",
            f"Expected a tuple of two current values, got: {result}",
        )
        # Calculate expected currents
        A = np.array([[R1+R2, -R2], [-R2, R2+R3]])
        b = np.array([V1, V2])
        expected = np.linalg.solve(A, b)
        I1_exp, I2_exp = expected[0], expected[1]
        _dynamic_test(
            self,
            np.isclose(result[0], I1_exp, atol=1e-6) and np.isclose(result[1], I2_exp, atol=1e-6),
            f"Returns correct currents for ({R1}, {R2}, {R3}, {V1}, {V2})",
            f"Expected currents ({I1_exp}, {I2_exp}), got {result}",
        )

    def test_nonzero_positive_resistors_and_voltages(self):
        import user_code
        importlib.reload(user_code)
        # All resistors and voltages are positive and nonzero
        R1, R2, R3, V1, V2 = 10, 20, 30, 40, 50
        result = user_code.solve_multi_loop_circuit(R1, R2, R3, V1, V2)
        _dynamic_test(
            self,
            result is not None and isinstance(result, tuple) and len(result) == 2,
            "Function returns a tuple of two values for all positive nonzero values.",
            f"Expected a tuple of two current values, got: {result}",
        )
        # Calculate expected currents
        A = np.array([[R1+R2, -R2], [-R2, R2+R3]])
        b = np.array([V1, V2])
        expected = np.linalg.solve(A, b)
        I1_exp, I2_exp = expected[0], expected[1]
        _dynamic_test(
            self,
            np.isclose(result[0], I1_exp, atol=1e-6) and np.isclose(result[1], I2_exp, atol=1e-6),
            f"Returns correct currents for ({R1}, {R2}, {R3}, {V1}, {V2})",
            f"Expected currents ({I1_exp}, {I2_exp}), got {result}",
        )

def _dynamic_test(test_case, condition, success_message, failure_message):
    if condition:
        test_case._testMethodName = success_message
        test_case.assertTrue(True, success_message)
    else:
        test_case._testMethodName = failure_message
        test_case.fail(failure_message)

def normalize_text(text):
    text = text.lower()
    text = re.sub(r"\\s{2,}", " ", text)
    text = re.sub(r"\\s*([,:?])\\s*", r"\\1 ", text)
    return text.strip()

def change_var(code: str, var_name: str, value: str) -> str:
    tree = ast.parse(code)
    lines = code.splitlines()
    changed = False
    # Collect all assignment nodes to modify
    assign_nodes = [
        (i, node)
        for i, node in enumerate(tree.body)
        if isinstance(node, ast.Assign)
        and any(isinstance(target, ast.Name) and target.id == var_name for target in node.targets)
    ]

    # If nothing to change, return unmodified code
    if not assign_nodes:
        return code

    # Perform replacements for all matching assignments (from last to first to not break line offsets)
    for i, node in reversed(assign_nodes):
        start_line = node.lineno - 1
        line = lines[start_line]
        indent = ' ' * (len(line) - len(line.lstrip()))
        lines[start_line] = f"{indent}{var_name} = {value}"
        next_line = len(lines)
        for next_node in tree.body[i+1:]:
            if hasattr(next_node, 'lineno'):
                next_line = next_node.lineno - 1
                break
        if next_line > start_line + 1:
            lines[start_line+1:next_line] = []
        changed = True

    return '\\n'.join(lines) if changed else code

if __name__ == "__main__":
    unittest.main()


test_main.py

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Challenge: Multi-Loop Circuit Solver

Soluzione

Challenge: Multi-Loop Circuit Solver

Soluzione