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Impara Challenge: Room Proportion Analyzer | Geometric Computation and Spatial Analysis
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Python for Architects

bookChallenge: Room Proportion Analyzer

Architects often need to quickly assess the proportions of different rooms to ensure they meet design standards and functional requirements. One way to do this is by classifying rooms based on their aspect ratios, which compare the width and length of a room. An aspect ratio close to 1:1 usually indicates a square room, while larger or smaller ratios suggest the room is either wide or narrow. In this challenge, you will write a function that analyzes a list of rooms, each with a specified width and length, and classifies their proportions as either 'Square', 'Wide', or 'Narrow'.

Compito

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Write a function called classify_room_proportions that takes a list of dictionaries, where each dictionary has keys "name", "width", and "length". The function should return a dictionary mapping each room name to its aspect ratio classification:

  • 'Square' if width and length differ by less than 10%.
  • 'Wide' if width is greater than length by 10% or more.
  • 'Narrow' if length is greater than width by 10% or more.

Use the following sample data for testing:

rooms = [
    {"name": "Gallery", "width": 6.0, "length": 6.5},
    {"name": "Studio", "width": 3.5, "length": 3.4},
    {"name": "Library", "width": 4.0, "length": 5.0},
    {"name": "Lounge", "width": 5.5, "length": 4.5},
    {"name": "Hall", "width": 7.0, "length": 7.0}
]

Your function should return:

{
    'Gallery': 'Narrow',
    'Studio': 'Square',
    'Library': 'Narrow',
    'Lounge': 'Wide',
    'Hall': 'Square'
}

Soluzione

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Sezione 2. Capitolo 7
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Suggested prompts:

Can you provide an example list of rooms to analyze?

What are the exact criteria for classifying a room as 'Square', 'Wide', or 'Narrow'?

Do you want the function to return the classifications as a list or print them directly?

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bookChallenge: Room Proportion Analyzer

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Architects often need to quickly assess the proportions of different rooms to ensure they meet design standards and functional requirements. One way to do this is by classifying rooms based on their aspect ratios, which compare the width and length of a room. An aspect ratio close to 1:1 usually indicates a square room, while larger or smaller ratios suggest the room is either wide or narrow. In this challenge, you will write a function that analyzes a list of rooms, each with a specified width and length, and classifies their proportions as either 'Square', 'Wide', or 'Narrow'.

Compito

Swipe to start coding

Write a function called classify_room_proportions that takes a list of dictionaries, where each dictionary has keys "name", "width", and "length". The function should return a dictionary mapping each room name to its aspect ratio classification:

  • 'Square' if width and length differ by less than 10%.
  • 'Wide' if width is greater than length by 10% or more.
  • 'Narrow' if length is greater than width by 10% or more.

Use the following sample data for testing:

rooms = [
    {"name": "Gallery", "width": 6.0, "length": 6.5},
    {"name": "Studio", "width": 3.5, "length": 3.4},
    {"name": "Library", "width": 4.0, "length": 5.0},
    {"name": "Lounge", "width": 5.5, "length": 4.5},
    {"name": "Hall", "width": 7.0, "length": 7.0}
]

Your function should return:

{
    'Gallery': 'Narrow',
    'Studio': 'Square',
    'Library': 'Narrow',
    'Lounge': 'Wide',
    'Hall': 'Square'
}

Soluzione

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Tutto è chiaro?

Come possiamo migliorarlo?

Grazie per i tuoi commenti!

Sezione 2. Capitolo 7
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