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Impara Pointers Use Cases | Pointers Fundamentals
C++ Pointers and References
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Contenuti del Corso

C++ Pointers and References

C++ Pointers and References

1. Pointers Fundamentals
2. Pointer Arithmetic
3. References Fundamentals
4. Dynamic Memory Allocation

book
Pointers Use Cases

When you pass a variable to a function, you're essentially passing its value. This means the function receives a copy of the data. Any modifications made inside the function do not affect the original variable.

cpp

main

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#include <iostream> void increment(int num) { num++; } int main() { int num = 5; increment(num); std::cout << "Original value: " << num << std::endl; }

We can use pointers to enable a function to alter the original variable. This involves passing a memory address as an argument instead of the actual value.

cpp

main

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#include <iostream> void increment(int* num) { (*num)++; } int main() { int num = 5; int* p_num = &num; increment(p_num); std::cout << "Original value: " << num << std::endl; }

Note

You can bypass the creation of a pointer to a variable and instead directly use the address-of operator when passing a variable.

Compito

Swipe to start coding

  1. Create a function that swaps values of two variables.
  2. Call this function.
  3. Output the values of variables after the swap.

Soluzione

cpp

solution

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Sezione 1. Capitolo 4
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book
Pointers Use Cases

When you pass a variable to a function, you're essentially passing its value. This means the function receives a copy of the data. Any modifications made inside the function do not affect the original variable.

cpp

main

copy
12345678910
#include <iostream> void increment(int num) { num++; } int main() { int num = 5; increment(num); std::cout << "Original value: " << num << std::endl; }

We can use pointers to enable a function to alter the original variable. This involves passing a memory address as an argument instead of the actual value.

cpp

main

copy
123456789101112
#include <iostream> void increment(int* num) { (*num)++; } int main() { int num = 5; int* p_num = &num; increment(p_num); std::cout << "Original value: " << num << std::endl; }

Note

You can bypass the creation of a pointer to a variable and instead directly use the address-of operator when passing a variable.

Compito

Swipe to start coding

  1. Create a function that swaps values of two variables.
  2. Call this function.
  3. Output the values of variables after the swap.

Soluzione

cpp

solution

Switch to desktopCambia al desktop per esercitarti nel mondo realeContinua da dove ti trovi utilizzando una delle opzioni seguenti
Tutto è chiaro?

Come possiamo migliorarlo?

Grazie per i tuoi commenti!

Sezione 1. Capitolo 4
Switch to desktopCambia al desktop per esercitarti nel mondo realeContinua da dove ti trovi utilizzando una delle opzioni seguenti
Siamo spiacenti che qualcosa sia andato storto. Cosa è successo?
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