Impara Nested Structs | Struct Usage

Nested structs allow you to represent more complex, hierarchical data by defining a struct within another struct. This is useful when modeling real-world objects that naturally contain other objects as part of their structure. For example, a Person might have an Address as one of its properties. By nesting an Address struct inside a Person struct, you can group related information together and keep your code organized and easy to understand.

main.cpp


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#include <iostream>
#include <string>

struct Address {
    std::string street;
    std::string city;
    int zipCode;
};

struct Person {
    std::string name;
    int age;
    Address address;
};

int main()
{
    Address addr;
    addr.street = "123 Maple Ave";
    addr.city = "Springfield";
    addr.zipCode = 12345;

    Person person;
    person.name = "Alice";
    person.age = 30;
    person.address = addr;

    std::cout << "Name: " << person.name << std::endl;
    std::cout << "Age: " << person.age << std::endl;
    std::cout << "Address: " << person.address.street << ", "
              << person.address.city << ", "
              << person.address.zipCode << std::endl;
}

To access or modify a member of a nested struct, use the dot operator (.) repeatedly. For instance, if you have a Person variable called person, you can access the city in their address with person.address.city. This approach allows you to work with deeply structured data in a clear and straightforward way. If you need to update the zip code, you can assign a new value like person.address.zipCode = 54321;. This makes it easy to manage and manipulate nested information within your structs.

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Sezione 2. Capitolo 1

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main.cpp


              123456789101112131415161718192021222324252627282930313233
            
#include <iostream>
#include <string>

struct Address {
    std::string street;
    std::string city;
    int zipCode;
};

struct Person {
    std::string name;
    int age;
    Address address;
};

int main()
{
    Address addr;
    addr.street = "123 Maple Ave";
    addr.city = "Springfield";
    addr.zipCode = 12345;

    Person person;
    person.name = "Alice";
    person.age = 30;
    person.address = addr;

    std::cout << "Name: " << person.name << std::endl;
    std::cout << "Age: " << person.age << std::endl;
    std::cout << "Address: " << person.address.street << ", "
              << person.address.city << ", "
              << person.address.zipCode << std::endl;
}

Tutto è chiaro?

Grazie per i tuoi commenti!

Sezione 2. Capitolo 1