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Impara Challenge: Investigation | Working with Dates and Times in pandas
Dealing with Dates and Times in Python
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Dealing with Dates and Times in Python

Dealing with Dates and Times in Python

1. Working with Dates
2. Working with Times
3. Timezones and Daylight Savings Time (DST)
4. Working with Dates and Times in pandas

book
Challenge: Investigation

As you noticed from the previous chapter, there are trips with negative and extremely huge durations (like more than 50 days). Surely this data can not be real, and we need to fix it if we want to go further.

What is the reason for extremely long trips? Most likely, it happened because some drivers forgot to turn off the taximeter when done with the route. The easiest way to deal with it - is simply to remove them as outliers. We will remove all the observations with durations greater-equal than 2 days (1-day duration will be investigated).

But what can be the real reason for negative durations? Let's try to find it out. Do not forget about timedelta objects, since we want to compare durations (measured in hours, minutes, and seconds; rarely, in days).

To not convert both columns to datetime every time, we can set parse_dates argument within .read_csv function to list with column names we want to convert.

Compito

Swipe to start coding

  1. Remove from df dataframe rows with abnormally long trips (duration is greater-equal than 2 days).
  2. Extract the first 10 rows with the negative trip duration (duration column).

Soluzione

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Tutto è chiaro?

Come possiamo migliorarlo?

Grazie per i tuoi commenti!

Sezione 4. Capitolo 4
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book
Challenge: Investigation

As you noticed from the previous chapter, there are trips with negative and extremely huge durations (like more than 50 days). Surely this data can not be real, and we need to fix it if we want to go further.

What is the reason for extremely long trips? Most likely, it happened because some drivers forgot to turn off the taximeter when done with the route. The easiest way to deal with it - is simply to remove them as outliers. We will remove all the observations with durations greater-equal than 2 days (1-day duration will be investigated).

But what can be the real reason for negative durations? Let's try to find it out. Do not forget about timedelta objects, since we want to compare durations (measured in hours, minutes, and seconds; rarely, in days).

To not convert both columns to datetime every time, we can set parse_dates argument within .read_csv function to list with column names we want to convert.

Compito

Swipe to start coding

  1. Remove from df dataframe rows with abnormally long trips (duration is greater-equal than 2 days).
  2. Extract the first 10 rows with the negative trip duration (duration column).

Soluzione

Switch to desktopCambia al desktop per esercitarti nel mondo realeContinua da dove ti trovi utilizzando una delle opzioni seguenti
Tutto è chiaro?

Come possiamo migliorarlo?

Grazie per i tuoi commenti!

Sezione 4. Capitolo 4
Switch to desktopCambia al desktop per esercitarti nel mondo realeContinua da dove ti trovi utilizzando una delle opzioni seguenti
Siamo spiacenti che qualcosa sia andato storto. Cosa è successo?
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