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Intermediate SQL
セクション 1. 章 7
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bookSeveral Aggregate Functions in the Query

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The school now knows the last names of those students who received more than one grade for exams, and the administration has decided to calculate the average grade from multiple grades of these students, and that will be their final grade.

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You should retrieve the last names of students with more than one exam grade and also calculate the average grade from all their grades. In the response, you should have 2 columns: the first one is the student_surname, and the second one is the average_grade. Use AVG() and COUNT() aggregate functions in this task.

Also, sort the result by the student_surname column in the ascending order.

Brief Instructions

  • Retrieve the student_surname column and the average of the grade column using the AVG function.
  • Assign the alias average_grade to the second column.
  • Group the data by student_surname.
  • Use the HAVING clause to filter the results based on COUNT(grade) > 1.
  • Sort the results by student_surname.

解答

Switch to desktop実践的な練習のためにデスクトップに切り替える下記のオプションのいずれかを利用して、現在の場所から続行する
すべて明確でしたか？

どのように改善できますか？

フィードバックありがとうございます！

セクション 1. 章 7
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