セクション 1. 章 14
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Challenge: Combining Table Results
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Your task will be to combine the employees and contractors tables using the UNION clause.
After that, from the resulting table, you should retrieve only those IDs that are multiples of 2. Also, you need to retrieve the first_name and last_name columns. Use the syntax WHERE id % 2 = 0. For this task, you need to use subqueries in the FROM section just as shown in the example.
As a result, you should have 3 columns: id (an alias for the ID from both tables), first_name, last_name.
Brief Instructions
- Retrieve the
id,first_name, andlast_namecolumns. - In the
FROMclause, write two inner queries joined by theUNIONclause. - In the first inner query, select
employee_id,first_name, andlast_namefrom theemployeestable.- Assign the alias
idtoemployee_id.
- Assign the alias
- In the second inner query, select
contractor_id,first_name, andlast_namefrom thecontractorstable.- Assign the alias
idtocontractor_id.
- Assign the alias
- Assign the alias
combinedto both inner queries. - Finally, use a
WHEREclause with the conditionid % 2 = 0.
id % 2 == 0 checks if id is even. The % operator returns the remainder after division, so if dividing by 2 leaves no remainder, the number is even.
解答
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セクション 1. 章 14
single
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