Decipher Binary Number

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So far, so good 😃 Convert binary code to the decimal one. Fill the gaps and follow the algorithm. The result of your manipulations is a specific number in math .

Create variable decimal_number for storing converted decimal number and assign 0 to it.
Print the binary number.
Define the variable power and assign 0 to it.
Define the loop that executes till the binary number is 0.
Count the remainder of division binary_number by 10 and assign it to the variable last_digit.
Multiply last_digit by the 2 raised to the relevant power.
Add the result to the decimal_number.
Decrease binary_number using integer division by 10.
Increase power by 1.
Print the decimal number.

Oplossing

binary_number = 101110010

decimal_number = 0

print("The number in binary numeral system is:", binary_number)

power = 0

while binary_number != 0:

last_digit = binary_number % 10

result = last_digit * pow(2, power)

decimal_number = decimal_number + result

binary_number = binary_number // 10

power = power + 1

# Printing the result

print("The number in decimal numeral system is:", decimal_number)

Note

You received one of the Armstrong number: the sum of the cubes of its own digits, let me explain this: 370 = 3^3 + 7^3 + 0^3 = 27 + 343 + 0 = 370

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Sectie 1. Hoofdstuk 3

binary_number = 101110010

# Create variable decimal_number for storing converted decimal number and assign 0 to it

___ = ___

# Output the binary number

print("The number in binary numeral system is: ", ___)

# Define the variable power and assign 0 to it

___ = ___

# Define the loop that executes till the number is zero

___ binary_number != ___:

# Count the remainder of division binary_number by 10 and assign it to the variable last_digit

___ = binary_number ___

# Multiply digit by the 2 raised to the relevant power

result = last_digit * pow(____, ____)

# Add the result to the decimal_number

decimal_number = decimal_number ___ result

# Decrease binary_number using integer division by 10

binary_number = binary_number ___ 10

# Increase power by 1

power = power ___ 1

# Output the decimal number

print("The number in decimal numeral system is: ", ______)

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