Filtering and Sorting Architectural Data
Architects often need to sift through large sets of room data to answer specific design questions. Filtering and sorting are essential techniques that help you quickly identify which rooms meet certain criteria, such as finding all rooms larger than 20 square meters or ranking spaces by how many people they can hold. For example, you might want to select only those rooms that are suitable for group activities or prioritize rooms for renovation based on their current occupancy. By using these methods, you can make data-driven decisions that directly impact your design process and project outcomes.
12345678910111213import pandas as pd # Sample DataFrame with room data data = { "room_name": ["Lobby", "Conference", "Office1", "Office2", "Studio", "Lounge"], "area_sqm": [35, 28, 18, 22, 45, 16], "occupancy": [10, 8, 2, 3, 6, 4] } df = pd.DataFrame(data) # Filter for rooms larger than 20 sqm and sort by occupancy (descending) filtered_sorted = df[df["area_sqm"] > 20].sort_values(by="occupancy", ascending=False) print(filtered_sorted)
By filtering and sorting your room data, you can immediately focus on the spaces that are most relevant to your current design question. In the filtered and sorted DataFrame above, only rooms larger than 20 square meters are considered, and those rooms are ranked by their occupancy. This approach allows you to prioritize which rooms to design for high-traffic areas, plan renovations, or allocate resources more effectively. Filtering narrows down the dataset to what matters most, while sorting helps you see which options are most significant for your goals.
123# Find the top 3 largest rooms with occupancy above 2 top_rooms = df[df["occupancy"] > 2].sort_values(by="area_sqm", ascending=False).head(3) print(top_rooms)
1. What pandas method is used to filter rows based on a condition?
2. How does sorting architectural data help in project planning?
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Can you explain how to filter rooms based on different criteria?
How can I sort the rooms by other attributes, like area or name?
What if I want to find rooms suitable for a specific number of people?
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Filtering and Sorting Architectural Data
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Architects often need to sift through large sets of room data to answer specific design questions. Filtering and sorting are essential techniques that help you quickly identify which rooms meet certain criteria, such as finding all rooms larger than 20 square meters or ranking spaces by how many people they can hold. For example, you might want to select only those rooms that are suitable for group activities or prioritize rooms for renovation based on their current occupancy. By using these methods, you can make data-driven decisions that directly impact your design process and project outcomes.
12345678910111213import pandas as pd # Sample DataFrame with room data data = { "room_name": ["Lobby", "Conference", "Office1", "Office2", "Studio", "Lounge"], "area_sqm": [35, 28, 18, 22, 45, 16], "occupancy": [10, 8, 2, 3, 6, 4] } df = pd.DataFrame(data) # Filter for rooms larger than 20 sqm and sort by occupancy (descending) filtered_sorted = df[df["area_sqm"] > 20].sort_values(by="occupancy", ascending=False) print(filtered_sorted)
By filtering and sorting your room data, you can immediately focus on the spaces that are most relevant to your current design question. In the filtered and sorted DataFrame above, only rooms larger than 20 square meters are considered, and those rooms are ranked by their occupancy. This approach allows you to prioritize which rooms to design for high-traffic areas, plan renovations, or allocate resources more effectively. Filtering narrows down the dataset to what matters most, while sorting helps you see which options are most significant for your goals.
123# Find the top 3 largest rooms with occupancy above 2 top_rooms = df[df["occupancy"] > 2].sort_values(by="area_sqm", ascending=False).head(3) print(top_rooms)
1. What pandas method is used to filter rows based on a condition?
2. How does sorting architectural data help in project planning?
Bedankt voor je feedback!