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Leer Insertion Sort | Simple Algorithms
Sorting Algorithms
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Cursusinhoud

Sorting Algorithms

Sorting Algorithms

1. Simple Algorithms
2. Divide and Conquer Algorithms
3. Problems

book
Insertion Sort

Insertion Sort is another simple sort algorithm that works with sorted and unsorted parts of an array. Values from unsorted part picked and placed to correct position in sorted part.

Example1

Example 2

[4 | 3 2 10 12 1 4 6] -> [3 4 | 2 10 12 1 4 6]

[3 4 | 2 10 12 1 4 6] -> [2 3 4 | 10 12 1 4 6]

[2 3 4 | 10 12 1 4 6]-> [2 3 4 10 | 12 1 4 6]

[2 3 4 10 | 12 1 4 6] -> [2 3 4 10 12 | 1 4 6]

[2 3 4 10 12 | 1 4 6] -> [1 2 3 4 10 12 | 4 6]

[1 2 3 4 10 12 | 4 6] -> [1 2 3 4 4 10 12 | 6]

[1 2 3 4 4 10 12 | 6] -> [1 2 3 4 4 6 10 12]

Time complexity is O(N^2), because each next element of an unsorted part iterates through elements of the sorted part. There are two nested loops in the algorithm.

Space complexity: O(1).

123456789101112131415
def insertionSort(arr): # Iterate unsorted subarrays for i in range(1, len(arr)): key = arr[i] # Element to move j = i-1 # Iterate sorted part and replace elements one position right while j>=0 and key < arr[j]: arr[j+1] = arr[j] j-=1 # Put key element on its position arr[j+1]= key return arr
copy
Taak

Swipe to start coding

Use the insertionSort() function to sort an array. You can either use the existing function or implement it yourself. Output the sorted array.

Oplossing

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Was alles duidelijk?

Hoe kunnen we het verbeteren?

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Sectie 1. Hoofdstuk 4
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book
Insertion Sort

Insertion Sort is another simple sort algorithm that works with sorted and unsorted parts of an array. Values from unsorted part picked and placed to correct position in sorted part.

Example1

Example 2

[4 | 3 2 10 12 1 4 6] -> [3 4 | 2 10 12 1 4 6]

[3 4 | 2 10 12 1 4 6] -> [2 3 4 | 10 12 1 4 6]

[2 3 4 | 10 12 1 4 6]-> [2 3 4 10 | 12 1 4 6]

[2 3 4 10 | 12 1 4 6] -> [2 3 4 10 12 | 1 4 6]

[2 3 4 10 12 | 1 4 6] -> [1 2 3 4 10 12 | 4 6]

[1 2 3 4 10 12 | 4 6] -> [1 2 3 4 4 10 12 | 6]

[1 2 3 4 4 10 12 | 6] -> [1 2 3 4 4 6 10 12]

Time complexity is O(N^2), because each next element of an unsorted part iterates through elements of the sorted part. There are two nested loops in the algorithm.

Space complexity: O(1).

123456789101112131415
def insertionSort(arr): # Iterate unsorted subarrays for i in range(1, len(arr)): key = arr[i] # Element to move j = i-1 # Iterate sorted part and replace elements one position right while j>=0 and key < arr[j]: arr[j+1] = arr[j] j-=1 # Put key element on its position arr[j+1]= key return arr
copy
Taak

Swipe to start coding

Use the insertionSort() function to sort an array. You can either use the existing function or implement it yourself. Output the sorted array.

Oplossing

Switch to desktopSchakel over naar desktop voor praktijkervaringGa verder vanaf waar je bent met een van de onderstaande opties
Was alles duidelijk?

Hoe kunnen we het verbeteren?

Bedankt voor je feedback!

Sectie 1. Hoofdstuk 4
Switch to desktopSchakel over naar desktop voor praktijkervaringGa verder vanaf waar je bent met een van de onderstaande opties
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