Numerical Integration with scipy.integrate
Numerical integration allows you to compute the area under curves and solve equations that do not have analytical solutions. In scientific computing, you often encounter the need to evaluate definite integrals or solve ordinary differential equations (ODEs) where exact solutions are either unknown or too complex to obtain. The scipy.integrate module in SciPy provides powerful and easy-to-use tools for these tasks, making it possible to perform integration and solve ODEs numerically using just a few lines of python code.
1234567891011from scipy import integrate import numpy as np # Define the function to integrate def f(x): return np.sin(x) # Compute the definite integral of sin(x) from 0 to pi result, error = integrate.quad(f, 0, np.pi) print("Integral result:", result) print("Estimated error:", error)
1234567891011121314151617181920212223from scipy.integrate import solve_ivp import numpy as np import matplotlib.pyplot as plt # Define the ODE: dy/dt = -2y def dydt(t, y): return -2 * y # Initial condition y0 = [1] # Time span for the solution t_span = (0, 5) # Solve the ODE solution = solve_ivp(dydt, t_span, y0, t_eval=np.linspace(0, 5, 100)) # Plot the solution plt.plot(solution.t, solution.y[0]) plt.xlabel("t") plt.ylabel("y(t)") plt.title("Solution of dy/dt = -2y with y(0) = 1") plt.show()
When you use scipy.integrate.quad, the function returns both the computed value of the integral and an estimate of the error. In the example above, integrating sin(x) from 0 to π gives a result very close to 2, which matches the exact analytical result. This demonstrates both the accuracy and reliability of the numerical integration routine.
For ordinary differential equations, scipy.integrate.solve_ivp computes the solution over a specified interval. In the ODE example, the equation dy/dt = -2y with the initial condition y(0) = 1 describes exponential decay. The solution shows how y decreases smoothly over time, and you can visualize this with a simple plot. The output matches the expected analytical solution y(t) = exp(-2t).
1. Which function is used for definite integration in SciPy?
2. What does scipy.integrate.solve_ivp solve?
3. Why is numerical integration important in scientific computing?
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Numerical Integration with scipy.integrate
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Numerical integration allows you to compute the area under curves and solve equations that do not have analytical solutions. In scientific computing, you often encounter the need to evaluate definite integrals or solve ordinary differential equations (ODEs) where exact solutions are either unknown or too complex to obtain. The scipy.integrate module in SciPy provides powerful and easy-to-use tools for these tasks, making it possible to perform integration and solve ODEs numerically using just a few lines of python code.
1234567891011from scipy import integrate import numpy as np # Define the function to integrate def f(x): return np.sin(x) # Compute the definite integral of sin(x) from 0 to pi result, error = integrate.quad(f, 0, np.pi) print("Integral result:", result) print("Estimated error:", error)
1234567891011121314151617181920212223from scipy.integrate import solve_ivp import numpy as np import matplotlib.pyplot as plt # Define the ODE: dy/dt = -2y def dydt(t, y): return -2 * y # Initial condition y0 = [1] # Time span for the solution t_span = (0, 5) # Solve the ODE solution = solve_ivp(dydt, t_span, y0, t_eval=np.linspace(0, 5, 100)) # Plot the solution plt.plot(solution.t, solution.y[0]) plt.xlabel("t") plt.ylabel("y(t)") plt.title("Solution of dy/dt = -2y with y(0) = 1") plt.show()
When you use scipy.integrate.quad, the function returns both the computed value of the integral and an estimate of the error. In the example above, integrating sin(x) from 0 to π gives a result very close to 2, which matches the exact analytical result. This demonstrates both the accuracy and reliability of the numerical integration routine.
For ordinary differential equations, scipy.integrate.solve_ivp computes the solution over a specified interval. In the ODE example, the equation dy/dt = -2y with the initial condition y(0) = 1 describes exponential decay. The solution shows how y decreases smoothly over time, and you can visualize this with a simple plot. The output matches the expected analytical solution y(t) = exp(-2t).
1. Which function is used for definite integration in SciPy?
2. What does scipy.integrate.solve_ivp solve?
3. Why is numerical integration important in scientific computing?
Obrigado pelo seu feedback!