Зміст курсу
Numeral Systems 101
Numeral Systems 101
One More Ciphering Challenge
I appreciate your efforts a lot! Here you are going to dive deeper into ciphering and the last issue for you is converting a number from a decimal numeral system to a hexadecimal one. Try to do it using strings😉.
- You need to divide the number by 16, and take down the remainder of the division.
- If the number is greater than 9, you need to find a match in letters.
- Then you should calculate the received number and implement the first step to it.
- You can stop if division results in 0.
- Rewrite remainders in the reversed order.
# Implementing dictionary, but here the keys are numbers, because we are ciphering dictionary = {0: "0", 1: "1", 2: "2", 3: "3", 4: "4", 5: "5", 6: "6", 7: "7", 8: "8", 9: "9", 10:"A" , 11:"B", 12:"C", 13:"D", 14:"E", 15:"F"} # Defining the decimal number 64206 decimal_number = 64206 # The text should be realised here due to the reason that further the decimal number will be changed print("The number in decimal numeral system is:", decimal_number) # Creating a list for storing converted hex number hexadecimal_number = [] # The conformity for 0 in decimal numeration system is 0; hence, this condition implemented # The loop executes till the number is zero while decimal_number != 0: # Counting the remainder of division by 16 remainder = decimal_number % 16 # Appending the converted resulting number for creating hexadecimal number hexadecimal_number.append(str(dictionary[remainder])) # This operation allows to decrease number by 16 an work with integer part of new one decimal_number = decimal_number // 16 # Reversing the string hexadecimal_number = hexadecimal_number[::-1] # Concatenating elements hexadecimal_number = "".join(hexadecimal_number) # Printing the result print("The number in hexadecimal numeral system is:", hexadecimal_number)
Завдання
Time to hone your skills! Follow the algorithm and fill the gaps to receive a number in hex representation:
- Print the
decimal_number
variable. - Create an empty list for storing
hexadecimal_number
. - Define the loop which executes till the
decimal_number
is0
. - Count the
remainder
of divisiondecimal_number
by16
. - Make the string
hexadecimal_number
reversed. - Join all elements of the string
hexadecimal_number
.
Дякуємо за ваш відгук!
One More Ciphering Challenge
I appreciate your efforts a lot! Here you are going to dive deeper into ciphering and the last issue for you is converting a number from a decimal numeral system to a hexadecimal one. Try to do it using strings😉.
- You need to divide the number by 16, and take down the remainder of the division.
- If the number is greater than 9, you need to find a match in letters.
- Then you should calculate the received number and implement the first step to it.
- You can stop if division results in 0.
- Rewrite remainders in the reversed order.
# Implementing dictionary, but here the keys are numbers, because we are ciphering dictionary = {0: "0", 1: "1", 2: "2", 3: "3", 4: "4", 5: "5", 6: "6", 7: "7", 8: "8", 9: "9", 10:"A" , 11:"B", 12:"C", 13:"D", 14:"E", 15:"F"} # Defining the decimal number 64206 decimal_number = 64206 # The text should be realised here due to the reason that further the decimal number will be changed print("The number in decimal numeral system is:", decimal_number) # Creating a list for storing converted hex number hexadecimal_number = [] # The conformity for 0 in decimal numeration system is 0; hence, this condition implemented # The loop executes till the number is zero while decimal_number != 0: # Counting the remainder of division by 16 remainder = decimal_number % 16 # Appending the converted resulting number for creating hexadecimal number hexadecimal_number.append(str(dictionary[remainder])) # This operation allows to decrease number by 16 an work with integer part of new one decimal_number = decimal_number // 16 # Reversing the string hexadecimal_number = hexadecimal_number[::-1] # Concatenating elements hexadecimal_number = "".join(hexadecimal_number) # Printing the result print("The number in hexadecimal numeral system is:", hexadecimal_number)
Завдання
Time to hone your skills! Follow the algorithm and fill the gaps to receive a number in hex representation:
- Print the
decimal_number
variable. - Create an empty list for storing
hexadecimal_number
. - Define the loop which executes till the
decimal_number
is0
. - Count the
remainder
of divisiondecimal_number
by16
. - Make the string
hexadecimal_number
reversed. - Join all elements of the string
hexadecimal_number
.
Дякуємо за ваш відгук!
One More Ciphering Challenge
I appreciate your efforts a lot! Here you are going to dive deeper into ciphering and the last issue for you is converting a number from a decimal numeral system to a hexadecimal one. Try to do it using strings😉.
- You need to divide the number by 16, and take down the remainder of the division.
- If the number is greater than 9, you need to find a match in letters.
- Then you should calculate the received number and implement the first step to it.
- You can stop if division results in 0.
- Rewrite remainders in the reversed order.
# Implementing dictionary, but here the keys are numbers, because we are ciphering dictionary = {0: "0", 1: "1", 2: "2", 3: "3", 4: "4", 5: "5", 6: "6", 7: "7", 8: "8", 9: "9", 10:"A" , 11:"B", 12:"C", 13:"D", 14:"E", 15:"F"} # Defining the decimal number 64206 decimal_number = 64206 # The text should be realised here due to the reason that further the decimal number will be changed print("The number in decimal numeral system is:", decimal_number) # Creating a list for storing converted hex number hexadecimal_number = [] # The conformity for 0 in decimal numeration system is 0; hence, this condition implemented # The loop executes till the number is zero while decimal_number != 0: # Counting the remainder of division by 16 remainder = decimal_number % 16 # Appending the converted resulting number for creating hexadecimal number hexadecimal_number.append(str(dictionary[remainder])) # This operation allows to decrease number by 16 an work with integer part of new one decimal_number = decimal_number // 16 # Reversing the string hexadecimal_number = hexadecimal_number[::-1] # Concatenating elements hexadecimal_number = "".join(hexadecimal_number) # Printing the result print("The number in hexadecimal numeral system is:", hexadecimal_number)
Завдання
Time to hone your skills! Follow the algorithm and fill the gaps to receive a number in hex representation:
- Print the
decimal_number
variable. - Create an empty list for storing
hexadecimal_number
. - Define the loop which executes till the
decimal_number
is0
. - Count the
remainder
of divisiondecimal_number
by16
. - Make the string
hexadecimal_number
reversed. - Join all elements of the string
hexadecimal_number
.
Дякуємо за ваш відгук!
I appreciate your efforts a lot! Here you are going to dive deeper into ciphering and the last issue for you is converting a number from a decimal numeral system to a hexadecimal one. Try to do it using strings😉.
- You need to divide the number by 16, and take down the remainder of the division.
- If the number is greater than 9, you need to find a match in letters.
- Then you should calculate the received number and implement the first step to it.
- You can stop if division results in 0.
- Rewrite remainders in the reversed order.
# Implementing dictionary, but here the keys are numbers, because we are ciphering dictionary = {0: "0", 1: "1", 2: "2", 3: "3", 4: "4", 5: "5", 6: "6", 7: "7", 8: "8", 9: "9", 10:"A" , 11:"B", 12:"C", 13:"D", 14:"E", 15:"F"} # Defining the decimal number 64206 decimal_number = 64206 # The text should be realised here due to the reason that further the decimal number will be changed print("The number in decimal numeral system is:", decimal_number) # Creating a list for storing converted hex number hexadecimal_number = [] # The conformity for 0 in decimal numeration system is 0; hence, this condition implemented # The loop executes till the number is zero while decimal_number != 0: # Counting the remainder of division by 16 remainder = decimal_number % 16 # Appending the converted resulting number for creating hexadecimal number hexadecimal_number.append(str(dictionary[remainder])) # This operation allows to decrease number by 16 an work with integer part of new one decimal_number = decimal_number // 16 # Reversing the string hexadecimal_number = hexadecimal_number[::-1] # Concatenating elements hexadecimal_number = "".join(hexadecimal_number) # Printing the result print("The number in hexadecimal numeral system is:", hexadecimal_number)
Завдання
Time to hone your skills! Follow the algorithm and fill the gaps to receive a number in hex representation:
- Print the
decimal_number
variable. - Create an empty list for storing
hexadecimal_number
. - Define the loop which executes till the
decimal_number
is0
. - Count the
remainder
of divisiondecimal_number
by16
. - Make the string
hexadecimal_number
reversed. - Join all elements of the string
hexadecimal_number
.