Passing Custom Structures as Arguments

We can also pass structures (classes) as arguments of the function. We can do it the same as passing simple data type by using structure (class) name as a type specifier inside the function signature:

Like simple data types, we can pass custom structures (classes) by value, pointer, or reference.

passByValue

passByPointer

passByReference


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#include <iostream>
#include <string>

// Define a custom structure
struct Person {
    std::string name;
    int age;
};

// Function that takes a Person structure by value
void displayPersonInfo(Person p)
{
    std::cout << "Name: " << p.name << ", Age: " << p.age << std::endl;
}

int main()
{
    // Create a Person structure
    Person person1 = {"Alice", 30};

    // Call the function and pass the Person structure by value
    displayPersonInfo(person1);
}

Note

There is another more comfortable way to access the attribute of the structure via pointer: we can use the -> operator instead of (*).. For example:

p->name instead of (*p).name;

p->age instead of (*p).age

Завдання

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Let's create a function to calculate the student's average grade based on his scores in different subjects and display their overall performance.

We had already done this task using a 2-dimensional static array before, but now we will do it with a custom structure.
Your task is to modify the code in the following way:

The function must get the student argument by reference.
Calculate the student's average score inside the function (variable averageScore)
Call the function and pass the created student1 value as an argument of the created function.

Рішення

solution

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