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It is time to deal with three experiments; they are very similar, so firstly, let's recall some theory.

FunctionExplanation
binom.pmf(k, n, p)Calculate the probability to archive exactly k successes among n trials with the probability of success p
binom.sf(k, n, p)Calculate the probability to archive k or more successes among n trials with the probability of success p
binom.cdf(k, n, p)Calculate the probability to archive k or less successes among n trials with the probability of success p
Завдання

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Here, it would be best if we coped with several tasks.

  1. Calculate the probability that among 50 unique pictures, exactly 5 have a defect; the probability that a picture has a defect is 25%.
  2. Calculate the probability that at least 9(9 or more) employees are satisfied with their salary if we know that there are 20 workers in the project. The probability for the positive answer is 75% .
  3. Calculate the probability that 6 or fewer thefts this month will be revealed; we know that in the specific city, the amount of thefts is 10. The probability of revealing is 5%.

Рішення

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It is time to deal with three experiments; they are very similar, so firstly, let's recall some theory.

FunctionExplanation
binom.pmf(k, n, p)Calculate the probability to archive exactly k successes among n trials with the probability of success p
binom.sf(k, n, p)Calculate the probability to archive k or more successes among n trials with the probability of success p
binom.cdf(k, n, p)Calculate the probability to archive k or less successes among n trials with the probability of success p
Завдання

Swipe to start coding

Here, it would be best if we coped with several tasks.

  1. Calculate the probability that among 50 unique pictures, exactly 5 have a defect; the probability that a picture has a defect is 25%.
  2. Calculate the probability that at least 9(9 or more) employees are satisfied with their salary if we know that there are 20 workers in the project. The probability for the positive answer is 75% .
  3. Calculate the probability that 6 or fewer thefts this month will be revealed; we know that in the specific city, the amount of thefts is 10. The probability of revealing is 5%.

Рішення

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Все було зрозуміло?

Як ми можемо покращити це?

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Секція 3. Розділ 4
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