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Вивчайте Implementing Ridge and Lasso Regression | Regularization Fundamentals
Feature Selection and Regularization Techniques

bookImplementing Ridge and Lasso Regression

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import numpy as np from sklearn.linear_model import Ridge from sklearn.datasets import make_regression # Generate synthetic regression data X, y = make_regression(n_samples=100, n_features=5, noise=10, random_state=42) # Fit Ridge regression model ridge = Ridge(alpha=1.0) ridge.fit(X, y) # Extract coefficients and intercept print("Ridge coefficients:", ridge.coef_) print("Ridge intercept:", ridge.intercept_)
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After fitting a Ridge regression model, you interpret the coefficients in a similar way as with ordinary least squares regression: each value in ridge.coef_ represents the estimated effect of the corresponding feature on the target variable, holding other features constant. However, Ridge regression applies L2 regularization, which shrinks the coefficient values toward zero compared to an unregularized model. This shrinkage helps reduce model complexity and can improve generalization when features are correlated or the dataset is noisy. The intercept, given by ridge.intercept_, represents the predicted value when all features are zero.

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import numpy as np from sklearn.linear_model import Lasso from sklearn.datasets import make_regression # Generate synthetic regression data X, y = make_regression(n_samples=100, n_features=5, noise=10, random_state=42) # Fit Lasso regression model on the same data lasso = Lasso(alpha=1.0) lasso.fit(X, y) # Extract coefficients and intercept print("Lasso coefficients:", lasso.coef_) print("Lasso intercept:", lasso.intercept_)
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When you compare the outputs of Ridge and Lasso regression, you will notice a key difference: while Ridge shrinks all coefficients but rarely sets any exactly to zero, Lasso (which uses L1 regularization) can drive some coefficients to exactly zero. This means Lasso can effectively perform feature selection by removing less important features from the model. You might prefer Ridge when all features are believed to be relevant and you want to reduce their impact smoothly, especially in the presence of multicollinearity. Lasso is preferable when you suspect that only a subset of features are important and want the model to automatically select them by setting irrelevant coefficients to zero.

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bookImplementing Ridge and Lasso Regression

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1234567891011121314
import numpy as np from sklearn.linear_model import Ridge from sklearn.datasets import make_regression # Generate synthetic regression data X, y = make_regression(n_samples=100, n_features=5, noise=10, random_state=42) # Fit Ridge regression model ridge = Ridge(alpha=1.0) ridge.fit(X, y) # Extract coefficients and intercept print("Ridge coefficients:", ridge.coef_) print("Ridge intercept:", ridge.intercept_)
copy

After fitting a Ridge regression model, you interpret the coefficients in a similar way as with ordinary least squares regression: each value in ridge.coef_ represents the estimated effect of the corresponding feature on the target variable, holding other features constant. However, Ridge regression applies L2 regularization, which shrinks the coefficient values toward zero compared to an unregularized model. This shrinkage helps reduce model complexity and can improve generalization when features are correlated or the dataset is noisy. The intercept, given by ridge.intercept_, represents the predicted value when all features are zero.

1234567891011121314
import numpy as np from sklearn.linear_model import Lasso from sklearn.datasets import make_regression # Generate synthetic regression data X, y = make_regression(n_samples=100, n_features=5, noise=10, random_state=42) # Fit Lasso regression model on the same data lasso = Lasso(alpha=1.0) lasso.fit(X, y) # Extract coefficients and intercept print("Lasso coefficients:", lasso.coef_) print("Lasso intercept:", lasso.intercept_)
copy

When you compare the outputs of Ridge and Lasso regression, you will notice a key difference: while Ridge shrinks all coefficients but rarely sets any exactly to zero, Lasso (which uses L1 regularization) can drive some coefficients to exactly zero. This means Lasso can effectively perform feature selection by removing less important features from the model. You might prefer Ridge when all features are believed to be relevant and you want to reduce their impact smoothly, especially in the presence of multicollinearity. Lasso is preferable when you suspect that only a subset of features are important and want the model to automatically select them by setting irrelevant coefficients to zero.

question mark

Which statement best describes the key difference between Ridge and Lasso regression?

Select the correct answer

Все було зрозуміло?

Як ми можемо покращити це?

Дякуємо за ваш відгук!

Секція 1. Розділ 3
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