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Learn References and Dereferences | Pointers
C Basics

bookReferences and Dereferences

Pointers are built around two operators:

  • The address-of operator &.
  • The dereference operator *.

Address-of Operator

The address-of operator, represented by &, allows us to directly interact with our computer's RAM. Using & lets you obtain the actual memory address of an object.

Main.c

Main.c

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#include <stdio.h> int main() { int x = 100; printf("Value of variable: %d\n", x); printf("Address of variable into RAM: %p\n", &x); // using reference operator `&` for getting address return 0; }

Note

%p is the format specifier used for addresses (pointer).

Addresses are typically expressed in hexadecimal notation.

Think of the & operator as identifying your home's address using your name.

Dereference Operator

Conversely, the * operator gives you the resident's name when given their address. So, how can we employ this operator if we're not directly dealing with addresses? If you have an expression like &x, which returns the address of the x variable, applying the * operator to it (*&x) gives you the value of the variable stored at that address.

Note

Essentially, *&x is the same as x.

Main.c

Main.c

copy
1234567891011121314
#include <stdio.h> int main() { int x = 100; printf("Value of variable: %d\n", x); printf("Address of variable in RAM: %p\n", &x); // using reference operator `&` printf("Dereferencing address of variable: %d", *(&x)); // using dereference operator `*` return 0; }

Note

Don't mix up the dereference operator (*x) with the multiplication operator (x*y).

Task

Swipe to start coding

  • Create an integer array of 5 elements and populate it.
  • Retrieve the address of the third element.
  • Increment the address of the third element (i.e., address + 1).
  • Attempt to dereference the address obtained in the previous step.

Solution

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SectionΒ 6. ChapterΒ 2
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bookReferences and Dereferences

Swipe to show menu

Pointers are built around two operators:

  • The address-of operator &.
  • The dereference operator *.

Address-of Operator

The address-of operator, represented by &, allows us to directly interact with our computer's RAM. Using & lets you obtain the actual memory address of an object.

Main.c

Main.c

copy
123456789101112
#include <stdio.h> int main() { int x = 100; printf("Value of variable: %d\n", x); printf("Address of variable into RAM: %p\n", &x); // using reference operator `&` for getting address return 0; }

Note

%p is the format specifier used for addresses (pointer).

Addresses are typically expressed in hexadecimal notation.

Think of the & operator as identifying your home's address using your name.

Dereference Operator

Conversely, the * operator gives you the resident's name when given their address. So, how can we employ this operator if we're not directly dealing with addresses? If you have an expression like &x, which returns the address of the x variable, applying the * operator to it (*&x) gives you the value of the variable stored at that address.

Note

Essentially, *&x is the same as x.

Main.c

Main.c

copy
1234567891011121314
#include <stdio.h> int main() { int x = 100; printf("Value of variable: %d\n", x); printf("Address of variable in RAM: %p\n", &x); // using reference operator `&` printf("Dereferencing address of variable: %d", *(&x)); // using dereference operator `*` return 0; }

Note

Don't mix up the dereference operator (*x) with the multiplication operator (x*y).

Task

Swipe to start coding

  • Create an integer array of 5 elements and populate it.
  • Retrieve the address of the third element.
  • Increment the address of the third element (i.e., address + 1).
  • Attempt to dereference the address obtained in the previous step.

Solution

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Everything was clear?

How can we improve it?

Thanks for your feedback!

SectionΒ 6. ChapterΒ 2
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