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Python Data Structures
course content

Course Content

Python Data Structures

Python Data Structures

1. List
Creating a ListNested ListChallenge: Create a ListList IndexingList LengthLists Are MutableAppend() MethodInsert() MethodDeleting ElementsRemoving ElementsList Comprehensions
2. Dictionary
Creating a DictionaryChallenge: Craft the DictionaryExtraction of InformationAdding ItemsDel KeywordPop() MethodPopitem() MethodClear() MethodDictionary Comprehensions
3. Tuple
Creating a Tuple Accessing Elements of a TupleConcatenation of Tuples Delete a Tuple Update a TupleAdding Items Challenge: Concatenate Tuples
4. Set
Creating a SetAdd() MethodUpdate() MethodAccessing the Elements of a SetRemove() and Discard() MethodsClear() Method

Accessing the Elements of a Set

Since a set is an unordered collection, you can't access its elements by index because they don't have indices. However, you can verify whether an element exists within the set using the in keyword.

It's especially handy to use the in keyword with a for loop. Let's check out an example.


              
1234

            
set_1 = {"green", "red", "white", "blue", "black"}

for i in set_1:
    print(i)


              
1234

            
set_ = {"green", "red", "white", "blue", "black"}

print("red" in set_)
print("yellow" in set_)

Task

Here's your set:

You need to determine if "pear", "banana", and "lemon" are in the set.

Task

Here's your set:

You need to determine if "pear", "banana", and "lemon" are in the set.

Everything was clear?

Section 4. Chapter 4
toggle bottom row

Accessing the Elements of a Set

Since a set is an unordered collection, you can't access its elements by index because they don't have indices. However, you can verify whether an element exists within the set using the in keyword.

It's especially handy to use the in keyword with a for loop. Let's check out an example.


              
1234

            
set_1 = {"green", "red", "white", "blue", "black"}

for i in set_1:
    print(i)


              
1234

            
set_ = {"green", "red", "white", "blue", "black"}

print("red" in set_)
print("yellow" in set_)

Task

Here's your set:

You need to determine if "pear", "banana", and "lemon" are in the set.

Task

Here's your set:

You need to determine if "pear", "banana", and "lemon" are in the set.

Everything was clear?

Section 4. Chapter 4
toggle bottom row

Accessing the Elements of a Set

Since a set is an unordered collection, you can't access its elements by index because they don't have indices. However, you can verify whether an element exists within the set using the in keyword.

It's especially handy to use the in keyword with a for loop. Let's check out an example.


              
1234

            
set_1 = {"green", "red", "white", "blue", "black"}

for i in set_1:
    print(i)


              
1234

            
set_ = {"green", "red", "white", "blue", "black"}

print("red" in set_)
print("yellow" in set_)

Task

Here's your set:

You need to determine if "pear", "banana", and "lemon" are in the set.

Task

Here's your set:

You need to determine if "pear", "banana", and "lemon" are in the set.

Everything was clear?

Since a set is an unordered collection, you can't access its elements by index because they don't have indices. However, you can verify whether an element exists within the set using the in keyword.

It's especially handy to use the in keyword with a for loop. Let's check out an example.


              
1234

            
set_1 = {"green", "red", "white", "blue", "black"}

for i in set_1:
    print(i)


              
1234

            
set_ = {"green", "red", "white", "blue", "black"}

print("red" in set_)
print("yellow" in set_)

Task

Here's your set:

You need to determine if "pear", "banana", and "lemon" are in the set.

Section 4. Chapter 4
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