Course Content

Numeral Systems 101

1. Binary Numeral System

Welcome on Board!Get Acquainted with Binary Code Decipher Binary Number Decipher List of Binary Numbers Cipher Some Numbers Hone your Ciphering Skills Dates in Binary

2. Octal Numeral system

Get Acquainted with the Octal Numeral System Practice Ciphering

3. Hexadecimal Numeral system

Deciphering Challenge One More Ciphering Challenge

4. Revelation

Write the Code in One Line Harder Converting Converting Using Format Method

Welcome on Board!

Hi there!

Have you heard about numeral systems? If not, I suppose you used to work with one of them, the most popular one. It is called the decimal numeral system and describes all values, that you use in regular life, like 10,112,674 or 4. Indeed, there are three more commonly used systems like binary, octal, and hexadecimal, but we are going to get acquainted with them in the next chapters.

But why decimal? All numbers are ten-based we can simply decompose them to a thousand, hundred and dozens.

Rule

I'm going to explain it explicitly using the number 123. Imagine that each number has indices and the counting starting from the very right number: here we begin with the number 3 and assign it the index of 0. Subsequently, 2 has an index of 1, and 1 has an index of 2. Therefore, 3->0, 2->1, 1->2. To present a number in decimal representation we should multiply it by the ten raised to the power of index. For instance: 1x10^2=100, 2x10^1=20, 3x10^0=3; or we can say the decomposed number 123 consists of 100, 20, and 3.


              12345678910111213141516171819
            
# Defining decimal number
decimal_number = 123
# Variable for storing the power
power = 0
# Printing decimal number
print("The initial decimal number is", decimal_number)
print("Decomposed decimal number consists of:")
# Defining loop that executes till the number is zero
while decimal_number != 0:
    # The remainder of division by 10 allows us to receive the last digit of a number
    last_digit = decimal_number % 10
    # Multiplying last_digit by 10 raised to the relevant power
    result = last_digit * pow(10, power)
    #Decreasing decimal number using integer division by 10, allows getting rid of the last digit
    decimal_number = decimal_number // 10
    # Increasing power by 1
    power = power + 1
    # Printing decomposed number
    print(result)

Task

Swipe to show code editor

Gained knowledge should be practiced, it is a recipe for success! So now, it is time to present numbers in the decimal numeral system. Try to do it with the number 365🌍 You should follow the algorithm on the right and fill the gaps.

Define the variable titled power and assign 0 to it.
Define the loop that executes till the decimal_number is 0.
Count the remainder of division decimal_number by 10.
Multiply the last_digit by the 10 raised to the relevant power.
Decrease decimal_number using integer division by 10.
Print the result.

_{Once you've completed this task, click the button below the code to check your solution.}

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

Section 1. Chapter 1

Welcome on Board!

Hi there!

But why decimal? All numbers are ten-based we can simply decompose them to a thousand, hundred and dozens.

Rule


              12345678910111213141516171819
            
# Defining decimal number
decimal_number = 123
# Variable for storing the power
power = 0
# Printing decimal number
print("The initial decimal number is", decimal_number)
print("Decomposed decimal number consists of:")
# Defining loop that executes till the number is zero
while decimal_number != 0:
    # The remainder of division by 10 allows us to receive the last digit of a number
    last_digit = decimal_number % 10
    # Multiplying last_digit by 10 raised to the relevant power
    result = last_digit * pow(10, power)
    #Decreasing decimal number using integer division by 10, allows getting rid of the last digit
    decimal_number = decimal_number // 10
    # Increasing power by 1
    power = power + 1
    # Printing decomposed number
    print(result)

Task

Swipe to show code editor

Define the variable titled power and assign 0 to it.
Define the loop that executes till the decimal_number is 0.
Count the remainder of division decimal_number by 10.
Multiply the last_digit by the 10 raised to the relevant power.
Decrease decimal_number using integer division by 10.
Print the result.

_{Once you've completed this task, click the button below the code to check your solution.}

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

Section 1. Chapter 1

Welcome on Board!

Hi there!

But why decimal? All numbers are ten-based we can simply decompose them to a thousand, hundred and dozens.

Rule


              12345678910111213141516171819
            
# Defining decimal number
decimal_number = 123
# Variable for storing the power
power = 0
# Printing decimal number
print("The initial decimal number is", decimal_number)
print("Decomposed decimal number consists of:")
# Defining loop that executes till the number is zero
while decimal_number != 0:
    # The remainder of division by 10 allows us to receive the last digit of a number
    last_digit = decimal_number % 10
    # Multiplying last_digit by 10 raised to the relevant power
    result = last_digit * pow(10, power)
    #Decreasing decimal number using integer division by 10, allows getting rid of the last digit
    decimal_number = decimal_number // 10
    # Increasing power by 1
    power = power + 1
    # Printing decomposed number
    print(result)

Task

Swipe to show code editor

Define the variable titled power and assign 0 to it.
Define the loop that executes till the decimal_number is 0.
Count the remainder of division decimal_number by 10.
Multiply the last_digit by the 10 raised to the relevant power.
Decrease decimal_number using integer division by 10.
Print the result.

_{Once you've completed this task, click the button below the code to check your solution.}

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

Hi there!

But why decimal? All numbers are ten-based we can simply decompose them to a thousand, hundred and dozens.

Rule


              12345678910111213141516171819
            
# Defining decimal number
decimal_number = 123
# Variable for storing the power
power = 0
# Printing decimal number
print("The initial decimal number is", decimal_number)
print("Decomposed decimal number consists of:")
# Defining loop that executes till the number is zero
while decimal_number != 0:
    # The remainder of division by 10 allows us to receive the last digit of a number
    last_digit = decimal_number % 10
    # Multiplying last_digit by 10 raised to the relevant power
    result = last_digit * pow(10, power)
    #Decreasing decimal number using integer division by 10, allows getting rid of the last digit
    decimal_number = decimal_number // 10
    # Increasing power by 1
    power = power + 1
    # Printing decomposed number
    print(result)

Task

Swipe to show code editor

Define the variable titled power and assign 0 to it.
Define the loop that executes till the decimal_number is 0.
Count the remainder of division decimal_number by 10.
Multiply the last_digit by the 10 raised to the relevant power.
Decrease decimal_number using integer division by 10.
Print the result.

_{Once you've completed this task, click the button below the code to check your solution.}

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Section 1. Chapter 1

Switch to desktop for real-world practiceContinue from where you are using one of the options below