Course Content
Numeral Systems 101
2. Octal Numeral system
3. Hexadecimal Numeral system
Numeral Systems 101
Dates in Binary
We used to present a time as a combination of four items like a year, month, day, and the time actually, you got acquainted with binary code; hence, you know that the maximum possible value for binary code is byte which includes 8 bits. Consequently 8 bits for 4 items-> 32 bits at all, so only 32 bits for storing our date and time.
The time started on the first of January in the year 1970 at 00:00:00 in this system and as you have noticed the time pass, and unfortunately the memory has different properties, one of them is to have a limit; therefore, in one day our time has to stop. Recent surveys proved that it is going to happen on the 19th of January in 2038 year. Maybe you will be a developer who will find the solution to this issue 🤖.
**It will be 2,147,483,647 seconds after 1 January 1970 in 20:45:52 19th of January in 2038 **
Task
Convert 2,147,483,647 to the binary number. Note that here the American standard for writing numbers was used to better understand the value, but for python code, it is necessary to exclude all commas: python read commas as a separator, but you don't need to separate anything. Your task is still the same follow the algorithm and fill the gaps.
- Create an empty list for storing a converted
binary_number. - Define the loop that executes till the
decimal_numberis0. - Count the remainder of division
decimal_numberby2. - Append the
remainderto the list ofbinary numbers. - Decrease
decimal_numberby integer division by2. - Make the list of
binary numbersreversed.
Note
I suppose you recognized that it is 31 bits full, so one second left to Epochalypse😲.
Everything was clear?
Course Content
Numeral Systems 101
2. Octal Numeral system
3. Hexadecimal Numeral system
Numeral Systems 101
Dates in Binary
We used to present a time as a combination of four items like a year, month, day, and the time actually, you got acquainted with binary code; hence, you know that the maximum possible value for binary code is byte which includes 8 bits. Consequently 8 bits for 4 items-> 32 bits at all, so only 32 bits for storing our date and time.
The time started on the first of January in the year 1970 at 00:00:00 in this system and as you have noticed the time pass, and unfortunately the memory has different properties, one of them is to have a limit; therefore, in one day our time has to stop. Recent surveys proved that it is going to happen on the 19th of January in 2038 year. Maybe you will be a developer who will find the solution to this issue 🤖.
**It will be 2,147,483,647 seconds after 1 January 1970 in 20:45:52 19th of January in 2038 **
Task
Convert 2,147,483,647 to the binary number. Note that here the American standard for writing numbers was used to better understand the value, but for python code, it is necessary to exclude all commas: python read commas as a separator, but you don't need to separate anything. Your task is still the same follow the algorithm and fill the gaps.
- Create an empty list for storing a converted
binary_number. - Define the loop that executes till the
decimal_numberis0. - Count the remainder of division
decimal_numberby2. - Append the
remainderto the list ofbinary numbers. - Decrease
decimal_numberby integer division by2. - Make the list of
binary numbersreversed.
Note
I suppose you recognized that it is 31 bits full, so one second left to Epochalypse😲.
Everything was clear?
