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Numeral Systems 101

bookDecipher Binary Number

Task

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So far, so good πŸ˜ƒ Convert binary code to the decimal one. Fill the gaps and follow the algorithm. The result of your manipulations is a specific number in math .

  1. Create variable decimal_number for storing converted decimal number and assign 0 to it.
  2. Print the binary number.
  3. Define the variable power and assign 0 to it.
  4. Define the loop that executes till the binary number is 0.
  5. Count the remainder of division binary_number by 10 and assign it to the variable last_digit.
  6. Multiply last_digit by the 2 raised to the relevant power.
  7. Add the result to the decimal_number.
  8. Decrease binary_number using integer division by 10.
  9. Increase power by 1.
  10. Print the decimal number.

Solution

Note

You received one of the Armstrong number: the sum of the cubes of its own digits, let me explain this: 370 = 3^3 + 7^3 + 0^3 = 27 + 343 + 0 = 370

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SectionΒ 1. ChapterΒ 3
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bookDecipher Binary Number

Swipe to show menu

Task

Swipe to start coding

So far, so good πŸ˜ƒ Convert binary code to the decimal one. Fill the gaps and follow the algorithm. The result of your manipulations is a specific number in math .

  1. Create variable decimal_number for storing converted decimal number and assign 0 to it.
  2. Print the binary number.
  3. Define the variable power and assign 0 to it.
  4. Define the loop that executes till the binary number is 0.
  5. Count the remainder of division binary_number by 10 and assign it to the variable last_digit.
  6. Multiply last_digit by the 2 raised to the relevant power.
  7. Add the result to the decimal_number.
  8. Decrease binary_number using integer division by 10.
  9. Increase power by 1.
  10. Print the decimal number.

Solution

Note

You received one of the Armstrong number: the sum of the cubes of its own digits, let me explain this: 370 = 3^3 + 7^3 + 0^3 = 27 + 343 + 0 = 370

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Everything was clear?

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Completion rate improved to 7.14
SectionΒ 1. ChapterΒ 3
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