One More Ciphering Challenge

I appreciate your efforts a lot! Here you are going to dive deeper into ciphering and the last issue for you is converting a number from a decimal numeral system to a hexadecimal one. Try to do it using strings😉.

You need to divide the number by 16, and take down the remainder of the division.
If the number is greater than 9, you need to find a match in letters.
Then you should calculate the received number and implement the first step to it.
You can stop if division results in 0.
Rewrite remainders in the reversed order.


              1234567891011121314151617181920212223
            
# Implementing dictionary, but here the keys are numbers, because we are ciphering
dictionary = {0: "0", 1: "1", 2: "2", 3: "3", 4: "4", 5: "5", 6: "6", 7: "7", 8: "8", 9: "9", 10:"A" , 11:"B", 12:"C", 13:"D", 14:"E", 15:"F"}
# Defining the decimal number 64206
decimal_number = 64206
# The text should be realised here due to the reason that further the decimal number will be changed
print("The number in decimal numeral system is:", decimal_number)
# Creating a list for storing converted hex number
hexadecimal_number = []
# The conformity for 0 in decimal numeration system is 0; hence, this condition implemented
# The loop executes till the number is zero
while decimal_number != 0:
    # Counting the remainder of division by 16
    remainder = decimal_number % 16
    # Appending the converted resulting number for creating hexadecimal number
    hexadecimal_number.append(str(dictionary[remainder]))
    # This operation allows to decrease number by 16 an work with integer part of new one
    decimal_number = decimal_number // 16
# Reversing the string
hexadecimal_number = hexadecimal_number[::-1]
# Concatenating elements
hexadecimal_number = "".join(hexadecimal_number)
# Printing the result
print("The number in hexadecimal numeral system is:", hexadecimal_number)

Task

Time to hone your skills! Follow the algorithm and fill the gaps to receive a number in hex representation:

Print the decimal_number variable.
Create an empty list for storing hexadecimal_number.
Define the loop which executes till the decimal_number is 0.
Count the remainder of division decimal_number by 16.
Make the string hexadecimal_number reversed.
Join all elements of the string hexadecimal_number.

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Section 3. Chapter 2

One More Ciphering Challenge

You need to divide the number by 16, and take down the remainder of the division.
If the number is greater than 9, you need to find a match in letters.
Then you should calculate the received number and implement the first step to it.
You can stop if division results in 0.
Rewrite remainders in the reversed order.


              1234567891011121314151617181920212223
            
# Implementing dictionary, but here the keys are numbers, because we are ciphering
dictionary = {0: "0", 1: "1", 2: "2", 3: "3", 4: "4", 5: "5", 6: "6", 7: "7", 8: "8", 9: "9", 10:"A" , 11:"B", 12:"C", 13:"D", 14:"E", 15:"F"}
# Defining the decimal number 64206
decimal_number = 64206
# The text should be realised here due to the reason that further the decimal number will be changed
print("The number in decimal numeral system is:", decimal_number)
# Creating a list for storing converted hex number
hexadecimal_number = []
# The conformity for 0 in decimal numeration system is 0; hence, this condition implemented
# The loop executes till the number is zero
while decimal_number != 0:
    # Counting the remainder of division by 16
    remainder = decimal_number % 16
    # Appending the converted resulting number for creating hexadecimal number
    hexadecimal_number.append(str(dictionary[remainder]))
    # This operation allows to decrease number by 16 an work with integer part of new one
    decimal_number = decimal_number // 16
# Reversing the string
hexadecimal_number = hexadecimal_number[::-1]
# Concatenating elements
hexadecimal_number = "".join(hexadecimal_number)
# Printing the result
print("The number in hexadecimal numeral system is:", hexadecimal_number)

Task

Time to hone your skills! Follow the algorithm and fill the gaps to receive a number in hex representation:

Print the decimal_number variable.
Create an empty list for storing hexadecimal_number.
Define the loop which executes till the decimal_number is 0.
Count the remainder of division decimal_number by 16.
Make the string hexadecimal_number reversed.
Join all elements of the string hexadecimal_number.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

Section 3. Chapter 2

One More Ciphering Challenge

You need to divide the number by 16, and take down the remainder of the division.
If the number is greater than 9, you need to find a match in letters.
Then you should calculate the received number and implement the first step to it.
You can stop if division results in 0.
Rewrite remainders in the reversed order.


              1234567891011121314151617181920212223
            
# Implementing dictionary, but here the keys are numbers, because we are ciphering
dictionary = {0: "0", 1: "1", 2: "2", 3: "3", 4: "4", 5: "5", 6: "6", 7: "7", 8: "8", 9: "9", 10:"A" , 11:"B", 12:"C", 13:"D", 14:"E", 15:"F"}
# Defining the decimal number 64206
decimal_number = 64206
# The text should be realised here due to the reason that further the decimal number will be changed
print("The number in decimal numeral system is:", decimal_number)
# Creating a list for storing converted hex number
hexadecimal_number = []
# The conformity for 0 in decimal numeration system is 0; hence, this condition implemented
# The loop executes till the number is zero
while decimal_number != 0:
    # Counting the remainder of division by 16
    remainder = decimal_number % 16
    # Appending the converted resulting number for creating hexadecimal number
    hexadecimal_number.append(str(dictionary[remainder]))
    # This operation allows to decrease number by 16 an work with integer part of new one
    decimal_number = decimal_number // 16
# Reversing the string
hexadecimal_number = hexadecimal_number[::-1]
# Concatenating elements
hexadecimal_number = "".join(hexadecimal_number)
# Printing the result
print("The number in hexadecimal numeral system is:", hexadecimal_number)

Task

Time to hone your skills! Follow the algorithm and fill the gaps to receive a number in hex representation:

Print the decimal_number variable.
Create an empty list for storing hexadecimal_number.
Define the loop which executes till the decimal_number is 0.
Count the remainder of division decimal_number by 16.
Make the string hexadecimal_number reversed.
Join all elements of the string hexadecimal_number.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

You need to divide the number by 16, and take down the remainder of the division.
If the number is greater than 9, you need to find a match in letters.
Then you should calculate the received number and implement the first step to it.
You can stop if division results in 0.
Rewrite remainders in the reversed order.


              1234567891011121314151617181920212223
            
# Implementing dictionary, but here the keys are numbers, because we are ciphering
dictionary = {0: "0", 1: "1", 2: "2", 3: "3", 4: "4", 5: "5", 6: "6", 7: "7", 8: "8", 9: "9", 10:"A" , 11:"B", 12:"C", 13:"D", 14:"E", 15:"F"}
# Defining the decimal number 64206
decimal_number = 64206
# The text should be realised here due to the reason that further the decimal number will be changed
print("The number in decimal numeral system is:", decimal_number)
# Creating a list for storing converted hex number
hexadecimal_number = []
# The conformity for 0 in decimal numeration system is 0; hence, this condition implemented
# The loop executes till the number is zero
while decimal_number != 0:
    # Counting the remainder of division by 16
    remainder = decimal_number % 16
    # Appending the converted resulting number for creating hexadecimal number
    hexadecimal_number.append(str(dictionary[remainder]))
    # This operation allows to decrease number by 16 an work with integer part of new one
    decimal_number = decimal_number // 16
# Reversing the string
hexadecimal_number = hexadecimal_number[::-1]
# Concatenating elements
hexadecimal_number = "".join(hexadecimal_number)
# Printing the result
print("The number in hexadecimal numeral system is:", hexadecimal_number)

Task

Time to hone your skills! Follow the algorithm and fill the gaps to receive a number in hex representation:

Print the decimal_number variable.
Create an empty list for storing hexadecimal_number.
Define the loop which executes till the decimal_number is 0.
Count the remainder of division decimal_number by 16.
Make the string hexadecimal_number reversed.
Join all elements of the string hexadecimal_number.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Section 3. Chapter 2

Switch to desktop for real-world practiceContinue from where you are using one of the options below