If/else expressions with multiple conditions (1/2)
In the last example, you might notice that we didn't consider the case when revenue is exactly 2000. In that case, we suffer no losses, but at the same time have no profit. Surely there should be a way to modify our code to predict such things.
If you want to check one more condition after you've done another one, use elif
. It looks like follows:
123456if condition1: do something elif condition2: do another else: do nothing
A piece of code after the last else will be executed only when all the conditions above don't hold.
For example, remember our last example with string length. Let's modify it a bit and now let's call string large if it has more than 20 symbols, medium - if more than 10 (but surely less than 20), and small otherwise.
123456789101112131415161718192021# assign some medium string test = "medium string" # conditional statements if len(test) > 20: print("String: '", test, "' is large") elif len(test) > 10: print("String: '", test, "' is medium") else: print("String: '", test, "' is small") # one more checking test = "small" # conditional statement if len(test) > 20: print("String: '", test, "' is large") elif len(test) > 10: print("String: '", test, "' is medium") else: print("String: '", test, "' is small")
Swipe to start coding
Modify your code (from exercise about the small store) so if revenue will be exactly 2000 you will receive the message "We are in balance".
Solution
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If/else expressions with multiple conditions (1/2)
In the last example, you might notice that we didn't consider the case when revenue is exactly 2000. In that case, we suffer no losses, but at the same time have no profit. Surely there should be a way to modify our code to predict such things.
If you want to check one more condition after you've done another one, use elif
. It looks like follows:
123456if condition1: do something elif condition2: do another else: do nothing
A piece of code after the last else will be executed only when all the conditions above don't hold.
For example, remember our last example with string length. Let's modify it a bit and now let's call string large if it has more than 20 symbols, medium - if more than 10 (but surely less than 20), and small otherwise.
123456789101112131415161718192021# assign some medium string test = "medium string" # conditional statements if len(test) > 20: print("String: '", test, "' is large") elif len(test) > 10: print("String: '", test, "' is medium") else: print("String: '", test, "' is small") # one more checking test = "small" # conditional statement if len(test) > 20: print("String: '", test, "' is large") elif len(test) > 10: print("String: '", test, "' is medium") else: print("String: '", test, "' is small")
Swipe to start coding
Modify your code (from exercise about the small store) so if revenue will be exactly 2000 you will receive the message "We are in balance".
Solution
Thanks for your feedback!
single
Awesome!
Completion rate improved to 2.33
If/else expressions with multiple conditions (1/2)
Swipe to show menu
In the last example, you might notice that we didn't consider the case when revenue is exactly 2000. In that case, we suffer no losses, but at the same time have no profit. Surely there should be a way to modify our code to predict such things.
If you want to check one more condition after you've done another one, use elif
. It looks like follows:
123456if condition1: do something elif condition2: do another else: do nothing
A piece of code after the last else will be executed only when all the conditions above don't hold.
For example, remember our last example with string length. Let's modify it a bit and now let's call string large if it has more than 20 symbols, medium - if more than 10 (but surely less than 20), and small otherwise.
123456789101112131415161718192021# assign some medium string test = "medium string" # conditional statements if len(test) > 20: print("String: '", test, "' is large") elif len(test) > 10: print("String: '", test, "' is medium") else: print("String: '", test, "' is small") # one more checking test = "small" # conditional statement if len(test) > 20: print("String: '", test, "' is large") elif len(test) > 10: print("String: '", test, "' is medium") else: print("String: '", test, "' is small")
Swipe to start coding
Modify your code (from exercise about the small store) so if revenue will be exactly 2000 you will receive the message "We are in balance".
Solution
Thanks for your feedback!