Challenge: Employees With More Than Average Salary
When a subquery is written in the WHERE section, we can use the IN operator and comparison operators:
SELECT column1, ...
FROM table
WHERE column1 > (SELECT AGG(column2) FROM table)
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Find employees whose salary is above the average salary of all employees using a subquery in the WHERE section.
The resulting table should have 3 columns: first_name, last_name, and salary. Then, sort the result by salary from highest to lowest using ORDER BY.
Note
This syntax can be used as a great alternative to the
HAVINGclause.
Brief Instructions
- Retrieve the
first_name,last_name, andsalarycolumns from theemployeestable. - In the
WHEREclause, use an inner query with the syntaxsalary > [inner query]. - In the inner query, get the average value of the
salarycolumn from theemployeestable. - Sort the results by
salaryin descending order.
Solution
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Completion rate improved to 4Challenge: Employees With More Than Average Salary
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When a subquery is written in the WHERE section, we can use the IN operator and comparison operators:
SELECT column1, ...
FROM table
WHERE column1 > (SELECT AGG(column2) FROM table)
Swipe to start coding
Find employees whose salary is above the average salary of all employees using a subquery in the WHERE section.
The resulting table should have 3 columns: first_name, last_name, and salary. Then, sort the result by salary from highest to lowest using ORDER BY.
Note
This syntax can be used as a great alternative to the
HAVINGclause.
Brief Instructions
- Retrieve the
first_name,last_name, andsalarycolumns from theemployeestable. - In the
WHEREclause, use an inner query with the syntaxsalary > [inner query]. - In the inner query, get the average value of the
salarycolumn from theemployeestable. - Sort the results by
salaryin descending order.
Solution
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