Notice: This page requires JavaScript to function properly.
Please enable JavaScript in your browser settings or update your browser.Several Aggregate Functions in the Query | Grouping
Intermediate SQL
course content

Course Content

Intermediate SQL

Intermediate SQL

1. Grouping
GROUP BY ClauseOrder of StatementsChallenge: Total Ride Time for Each Subway LineAverage Student's Grade ChallengeSearching for the Top Math Students ChallengeHAVING ClauseSeveral Aggregate Functions in the QueryMore Complex Filtering
2. Nested Subqueries
Nested QueriesChallenge: Non-tech Department EmployeesUsing Inner Subqueries in the FROM SectionChallenge: Employees With More Than Average SalaryUNION ClauseChallenge: Combining Table Results
3. Joining Tables
JOIN 2 TablesChallenge: Get Category By Product PriceChallenge: Get Minimum Price By CategoryChallenge: Get Product Amount By CategoryLEFT, RIGHT and INNER JOINsChallenge: Table JoinChallenge: FULL JOIN Usage
4. DDL and DML in SQL
CREATE and ConstraintsALTER and INSERT OperationsDROP and TRUNCATEUPDATE and DELETE

book
Several Aggregate Functions in the Query

The school now knows the last names of those students who received more than one grade for exams, and the administration has decided to calculate the average grade from multiple grades of these students, and that will be their final grade.

Task
test

Swipe to show code editor

You should retrieve the last names of students with more than one exam grade and also calculate the average grade from all their grades. In the response, you should have 2 columns: the first one is the student_surname, and the second one is the average_grade. Use AVG() and COUNT() aggregate functions in this task.

Also, sort the result by the student_surname column in the ascending order.

Brief Instructions

  • Retrieve the student_surname column and the average of the grade column using the AVG function.
  • Assign the alias average_grade to the second column.
  • Group the data by student_surname.
  • Use the HAVING clause to filter the results based on COUNT(grade) > 1.
  • Sort the results by student_surname.

Solution

Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
Everything was clear?

How can we improve it?

Thanks for your feedback!

Section 1. Chapter 7
toggle bottom row

book
Several Aggregate Functions in the Query

The school now knows the last names of those students who received more than one grade for exams, and the administration has decided to calculate the average grade from multiple grades of these students, and that will be their final grade.

Task
test

Swipe to show code editor

You should retrieve the last names of students with more than one exam grade and also calculate the average grade from all their grades. In the response, you should have 2 columns: the first one is the student_surname, and the second one is the average_grade. Use AVG() and COUNT() aggregate functions in this task.

Also, sort the result by the student_surname column in the ascending order.

Brief Instructions

  • Retrieve the student_surname column and the average of the grade column using the AVG function.
  • Assign the alias average_grade to the second column.
  • Group the data by student_surname.
  • Use the HAVING clause to filter the results based on COUNT(grade) > 1.
  • Sort the results by student_surname.

Solution

Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
Everything was clear?

How can we improve it?

Thanks for your feedback!

Section 1. Chapter 7
Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
We're sorry to hear that something went wrong. What happened?
some-alt