Intermediate SQL

Intermediate SQL

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1. Grouping

In this section, you will learn how to group and manage data effectively. We will introduce the GROUP BY operator for grouping data. Additionally, you will learn how to filter grouped data using the HAVING operator.

Order of Statements

Total Ride Time for Each Subway Line Challenge

Average Student's Grade Challenge

Searching for the Top Math Students Challenge

Several Aggregate Functions in the Query

More Complex Filtering

2. Nested Subqueries

You will learn about nested subqueries, how to create them, and how to use them effectively.

Non-tech Department Employees Challenge

Using Inner Subqueries in the FROM Section

Employees With More Than Average Salary Challenge

Combining Table Results

3. Joining Tables

Here, you will learn how to combine multiple tables, allowing you to work with a unified table and simplify query creation.

Get Category By Product Price

Get Minimum Price By Category

Get Product Amount By Category

LEFT, RIGHT and INNER JOINs

Table Join Practice

FULL JOIN Usage

4. DDL and DML in SQL

Learn the fundamentals of Data Definition Language (DDL) and Data Manipulation Language (DML) in SQL, including how to create, modify, and delete database objects, as well as how to insert, update, and delete data within tables.

CREATE and Constraints

ALTER and INSERT Operations

DROP and TRUNCATE

UPDATE and DELETE

Several Aggregate Functions in the Query

The school now knows the last names of those students who received more than one grade for exams, and the administration has decided to calculate the average grade from multiple grades of these students, and that will be their final grade.

You have to do this.

Here is the preview of a student_grades table we are working with:

Task

Swipe to show code editor

You should retrieve the last names of students with more than one exam grade and also calculate the average grade from all their grades. In the response, you should have 2 columns: the first one is the student_surname, and the second one is the average_grade. Use AVG() and COUNT() aggregate functions in this task.

Also, sort the result by the student_surname column in the ascending order.

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Section 1. Chapter 7

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Several Aggregate Functions in the Query

The school now knows the last names of those students who received more than one grade for exams, and the administration has decided to calculate the average grade from multiple grades of these students, and that will be their final grade.

You have to do this.

Here is the preview of a student_grades table we are working with:

Task

Swipe to show code editor

You should retrieve the last names of students with more than one exam grade and also calculate the average grade from all their grades. In the response, you should have 2 columns: the first one is the student_surname, and the second one is the average_grade. Use AVG() and COUNT() aggregate functions in this task.

Also, sort the result by the student_surname column in the ascending order.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

Section 1. Chapter 7

toggle bottom row

Several Aggregate Functions in the Query

The school now knows the last names of those students who received more than one grade for exams, and the administration has decided to calculate the average grade from multiple grades of these students, and that will be their final grade.

You have to do this.

Here is the preview of a student_grades table we are working with:

Task

Swipe to show code editor

You should retrieve the last names of students with more than one exam grade and also calculate the average grade from all their grades. In the response, you should have 2 columns: the first one is the student_surname, and the second one is the average_grade. Use AVG() and COUNT() aggregate functions in this task.

Also, sort the result by the student_surname column in the ascending order.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

The school now knows the last names of those students who received more than one grade for exams, and the administration has decided to calculate the average grade from multiple grades of these students, and that will be their final grade.

You have to do this.

Here is the preview of a student_grades table we are working with:

Task

Swipe to show code editor

You should retrieve the last names of students with more than one exam grade and also calculate the average grade from all their grades. In the response, you should have 2 columns: the first one is the student_surname, and the second one is the average_grade. Use AVG() and COUNT() aggregate functions in this task.

Also, sort the result by the student_surname column in the ascending order.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Section 1. Chapter 7

Switch to desktop for real-world practiceContinue from where you are using one of the options below

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