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Intermediate SQL
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Intermediate SQL

Intermediate SQL

1. Grouping
GROUP BY ClauseOrder of StatementsChallenge: Total Ride Time for Each Subway LineAverage Student's Grade ChallengeSearching for the Top Math Students ChallengeHAVING ClauseSeveral Aggregate Functions in the QueryMore Complex Filtering
2. Nested Subqueries
Nested QueriesChallenge: Non-tech Department EmployeesUsing Inner Subqueries in the FROM SectionChallenge: Employees With More Than Average SalaryUNION ClauseChallenge: Combining Table Results
3. Joining Tables
JOIN 2 TablesChallenge: Get Category By Product PriceChallenge: Get Minimum Price By CategoryChallenge: Get Product Amount By CategoryLEFT, RIGHT and INNER JOINsChallenge: Table JoinChallenge: FULL JOIN Usage
4. DDL and DML in SQL
CREATE and ConstraintsALTER and INSERT OperationsDROP and TRUNCATEUPDATE and DELETE

book
Challenge: FULL JOIN Usage

In this chapter, you'll learn how to use a different type of table join. Unlike the previous chapters where you could use the same JOIN, this time you'll need to apply a specific one.

Task

Swipe to start coding

Write a query to retrieve a list of all courses and students, including those courses with no registered students and those students who are not registered for any course.

To accomplish this, you will need to use a specific type of join. Also, retrieve the columns in the exact order as specified:

git

Additionally, sort the result by the course_id column. Good luck!

Brief Instructions

  • Retrieve the necessary columns from the courses table.
  • Use a FULL JOIN to join the enrollments table.
  • The common column for both tables is courses.course_id = enrollments.course_id.
  • Sort the results by courses.course_id.

Solution

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SectionΒ 3. ChapterΒ 7
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book
Challenge: FULL JOIN Usage

In this chapter, you'll learn how to use a different type of table join. Unlike the previous chapters where you could use the same JOIN, this time you'll need to apply a specific one.

Task

Swipe to start coding

Write a query to retrieve a list of all courses and students, including those courses with no registered students and those students who are not registered for any course.

To accomplish this, you will need to use a specific type of join. Also, retrieve the columns in the exact order as specified:

git

Additionally, sort the result by the course_id column. Good luck!

Brief Instructions

  • Retrieve the necessary columns from the courses table.
  • Use a FULL JOIN to join the enrollments table.
  • The common column for both tables is courses.course_id = enrollments.course_id.
  • Sort the results by courses.course_id.

Solution

Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
Everything was clear?

How can we improve it?

Thanks for your feedback!

SectionΒ 3. ChapterΒ 7
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