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Learn Spectra and Spectral Decomposition | Spectral Foundations in Linear Algebra
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Spectral Methods in Machine Learning

bookSpectra and Spectral Decomposition

The spectrum of a matrix is the set of its eigenvalues. If you have a square matrix AA, and you have already learned to find its eigenvalues and eigenvectors, you can now refer to the collection of all eigenvalues as the spectrum of AA. This spectrum provides deep insight into the structure and behavior of the linear transformation represented by the matrix.

Note
Definition

Spectral Theorem for Symmetric Matrices:
If AA is a real symmetric matrix, then all its eigenvalues are real, and there exists an orthogonal matrix QQ such that A=QΞ›Q⊀A = Q\Lambda Q^\top, where Ξ›\Lambda is a diagonal matrix whose entries are the eigenvalues of AA. This means the spectrum of AA consists entirely of real numbers, and AA can be represented as a sum of projections onto its eigenvectors.

Intuition: Diagonalization as Change of Basis
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When you diagonalize a matrix, you are essentially finding a new basis in which the linear transformation acts by simply stretching or shrinking along each basis direction. In this new basis, the matrix becomes diagonal, and its action is easy to interpret: each coordinate is scaled by the corresponding eigenvalue.

  • Diagonalization means rewriting the matrix so its structure is clear and simple;
  • In the new basis, the transformation is just scaling, not mixing directions;
  • Each eigenvector points in a direction that is unchanged except for scaling by its eigenvalue.
Formal Statement: Spectral Decomposition and the Spectral Theorem
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The spectral decomposition of a real symmetric matrix AA expresses it as A=QΞ›Q⊀A = Q\Lambda Q^\top, where QQ is an orthogonal matrix whose columns are the normalized eigenvectors of AA, and Ξ›\Lambda is a diagonal matrix of eigenvalues (the spectrum).

  • This is a direct consequence of the Spectral Theorem;
  • Any symmetric matrix can be "untangled" into independent, one-dimensional actions along its eigenvector directions;
  • The action of AA becomes transparent: each direction is scaled by its corresponding eigenvalue.

Spectral decomposition has important consequences for understanding how matrices behave when raised to powers or when functions are applied to them. If a symmetric matrix AA is diagonalizable as A=QΞ›Q⊀A = Q\Lambda Q^\top, then computing powers like AkA^k becomes straightforward: Ak=QΞ›kQ⊀A^k = Q\Lambda^k Q^\top, where Ξ›k\Lambda^k is simply the diagonal matrix with each eigenvalue raised to the k-th power. This makes it much easier to analyze the long-term behavior of repeated transformations. Similarly, for any function ff applied to AA, such as the exponential or square root, you can compute f(A)=Qf(Ξ›)Q⊀f(A) = Q f(\Lambda) Q^\top, where f(Ξ›)f(\Lambda) is the diagonal matrix with ff applied to each eigenvalue. This diagonalization approach reveals why the spectrum is so powerful in simplifying complex matrix operations.

question mark

Why is diagonalization such a powerful tool for analyzing linear transformations?

Select the correct answer

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SectionΒ 1. ChapterΒ 2

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bookSpectra and Spectral Decomposition

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The spectrum of a matrix is the set of its eigenvalues. If you have a square matrix AA, and you have already learned to find its eigenvalues and eigenvectors, you can now refer to the collection of all eigenvalues as the spectrum of AA. This spectrum provides deep insight into the structure and behavior of the linear transformation represented by the matrix.

Note
Definition

Spectral Theorem for Symmetric Matrices:
If AA is a real symmetric matrix, then all its eigenvalues are real, and there exists an orthogonal matrix QQ such that A=QΞ›Q⊀A = Q\Lambda Q^\top, where Ξ›\Lambda is a diagonal matrix whose entries are the eigenvalues of AA. This means the spectrum of AA consists entirely of real numbers, and AA can be represented as a sum of projections onto its eigenvectors.

Intuition: Diagonalization as Change of Basis
expand arrow

When you diagonalize a matrix, you are essentially finding a new basis in which the linear transformation acts by simply stretching or shrinking along each basis direction. In this new basis, the matrix becomes diagonal, and its action is easy to interpret: each coordinate is scaled by the corresponding eigenvalue.

  • Diagonalization means rewriting the matrix so its structure is clear and simple;
  • In the new basis, the transformation is just scaling, not mixing directions;
  • Each eigenvector points in a direction that is unchanged except for scaling by its eigenvalue.
Formal Statement: Spectral Decomposition and the Spectral Theorem
expand arrow

The spectral decomposition of a real symmetric matrix AA expresses it as A=QΞ›Q⊀A = Q\Lambda Q^\top, where QQ is an orthogonal matrix whose columns are the normalized eigenvectors of AA, and Ξ›\Lambda is a diagonal matrix of eigenvalues (the spectrum).

  • This is a direct consequence of the Spectral Theorem;
  • Any symmetric matrix can be "untangled" into independent, one-dimensional actions along its eigenvector directions;
  • The action of AA becomes transparent: each direction is scaled by its corresponding eigenvalue.

Spectral decomposition has important consequences for understanding how matrices behave when raised to powers or when functions are applied to them. If a symmetric matrix AA is diagonalizable as A=QΞ›Q⊀A = Q\Lambda Q^\top, then computing powers like AkA^k becomes straightforward: Ak=QΞ›kQ⊀A^k = Q\Lambda^k Q^\top, where Ξ›k\Lambda^k is simply the diagonal matrix with each eigenvalue raised to the k-th power. This makes it much easier to analyze the long-term behavior of repeated transformations. Similarly, for any function ff applied to AA, such as the exponential or square root, you can compute f(A)=Qf(Ξ›)Q⊀f(A) = Q f(\Lambda) Q^\top, where f(Ξ›)f(\Lambda) is the diagonal matrix with ff applied to each eigenvalue. This diagonalization approach reveals why the spectrum is so powerful in simplifying complex matrix operations.

question mark

Why is diagonalization such a powerful tool for analyzing linear transformations?

Select the correct answer

Everything was clear?

How can we improve it?

Thanks for your feedback!

SectionΒ 1. ChapterΒ 2
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