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Python Loops Tutorial
course content

Course Content

Python Loops Tutorial

Python Loops Tutorial

1. The for Loop
The first for LoopRange() in a for Loop 1/2Range() in a for Loop 2/2List & for LoopIf/Else in a for LoopBreak/Continue in a for LoopPass, Else in a for LoopEnumerate() in a for LoopChallenge
2. The while Loop
The First while LoopInfinite LoopList & while LoopIf/Else in a while LoopBreak/Continue in a while LoopPass, Else in a while Loop
3. Nested Loops
First Nested Loop PatternNested for LoopNested while LoopWhile Loop inside a for LoopIf/Else in a Nested LoopBreak/Continue in a Nested LoopChallenge

bookIf/Else in a while Loop

We previously used the if/else structure in conjunction with for loops, and we can apply the same concept to while loops.

An if/else structure within a while loop functions when the while condition becomes False.

Examine the code below:


              
1234567891011

            
numbers = [1, 2, 4, 5, 7]
i = 0

# Checking even and odd
while i < len(numbers):
  if numbers[i] % 2 == 0:
    print(numbers[i], 'is an even number')
    i += 1
  else:
    print(numbers[i], 'is an odd number')
    i += 1
copy

How does the code work?

Task
test

Swipe to show code editor

Multiply all the negative numbers in the list.

  1. Initialize a while loop, utilizing i to interact with numbers.
  2. Establish the condition if an element is less than 0.
  3. Multiply the element and accumulate it in the counter.
  4. Update the value of i to change the list index.
  5. Display the value stored in the counter.

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Section 2. Chapter 4
toggle bottom row

bookIf/Else in a while Loop

We previously used the if/else structure in conjunction with for loops, and we can apply the same concept to while loops.

An if/else structure within a while loop functions when the while condition becomes False.

Examine the code below:


              
1234567891011

            
numbers = [1, 2, 4, 5, 7]
i = 0

# Checking even and odd
while i < len(numbers):
  if numbers[i] % 2 == 0:
    print(numbers[i], 'is an even number')
    i += 1
  else:
    print(numbers[i], 'is an odd number')
    i += 1
copy

How does the code work?

Task
test

Swipe to show code editor

Multiply all the negative numbers in the list.

  1. Initialize a while loop, utilizing i to interact with numbers.
  2. Establish the condition if an element is less than 0.
  3. Multiply the element and accumulate it in the counter.
  4. Update the value of i to change the list index.
  5. Display the value stored in the counter.

Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
Everything was clear?

How can we improve it?

Thanks for your feedback!

Section 2. Chapter 4
toggle bottom row

bookIf/Else in a while Loop

We previously used the if/else structure in conjunction with for loops, and we can apply the same concept to while loops.

An if/else structure within a while loop functions when the while condition becomes False.

Examine the code below:


              
1234567891011

            
numbers = [1, 2, 4, 5, 7]
i = 0

# Checking even and odd
while i < len(numbers):
  if numbers[i] % 2 == 0:
    print(numbers[i], 'is an even number')
    i += 1
  else:
    print(numbers[i], 'is an odd number')
    i += 1
copy

How does the code work?

Task
test

Swipe to show code editor

Multiply all the negative numbers in the list.

  1. Initialize a while loop, utilizing i to interact with numbers.
  2. Establish the condition if an element is less than 0.
  3. Multiply the element and accumulate it in the counter.
  4. Update the value of i to change the list index.
  5. Display the value stored in the counter.

Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
Everything was clear?

How can we improve it?

Thanks for your feedback!

We previously used the if/else structure in conjunction with for loops, and we can apply the same concept to while loops.

An if/else structure within a while loop functions when the while condition becomes False.

Examine the code below:


              
1234567891011

            
numbers = [1, 2, 4, 5, 7]
i = 0

# Checking even and odd
while i < len(numbers):
  if numbers[i] % 2 == 0:
    print(numbers[i], 'is an even number')
    i += 1
  else:
    print(numbers[i], 'is an odd number')
    i += 1
copy

How does the code work?

Task
test

Swipe to show code editor

Multiply all the negative numbers in the list.

  1. Initialize a while loop, utilizing i to interact with numbers.
  2. Establish the condition if an element is less than 0.
  3. Multiply the element and accumulate it in the counter.
  4. Update the value of i to change the list index.
  5. Display the value stored in the counter.

Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
Section 2. Chapter 4
Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
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