Course Content

Python Loops Tutorial

Break/Continue in a while Loop

Now, we'll attempt the same task we previously accomplished with the for loop—finding a number in the list and terminating the loop once it's located.

Examine the code below:


              12345678910
            
numbers = [2, 3, 4, 11, 5]
i = 0

# Breaking the loop, if 11 is found
while i < len(numbers):
  if numbers[i] == 11:
    print('11 is here!')
    break
  else:
    i = i + 1

How does the code work?

Great!

Please be aware that the continue statement skips a block of code within the loop for the current iteration only. Now, let's count the occurrences of 11s in the code using continue.

Examine the code below:


              123456789101112131415
            
numbers = [2, 11, 4, 11, 5]
i = -1
counter = 0

# Count all 11 in the list
# We are using len(numbers) - 1 to break the loop without being 'out of range'
while i < len(numbers) - 1:
  i = i + 1
  if numbers[i] != 11:
    continue
  else:
    print('11 is here!')
    counter += 1

print("Total number of '11': ", counter)

How does the code work?

Task

Halt the loop when encountering a negative value.

Initialize a while loop, employing i to interact with numbers.
Increment the value of i.
Display a message along with the negative element.
Employ break and continue as needed.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

Section 2. Chapter 5

Break/Continue in a while Loop

Now, we'll attempt the same task we previously accomplished with the for loop—finding a number in the list and terminating the loop once it's located.

Examine the code below:


              12345678910
            
numbers = [2, 3, 4, 11, 5]
i = 0

# Breaking the loop, if 11 is found
while i < len(numbers):
  if numbers[i] == 11:
    print('11 is here!')
    break
  else:
    i = i + 1

How does the code work?

Great!

Please be aware that the continue statement skips a block of code within the loop for the current iteration only. Now, let's count the occurrences of 11s in the code using continue.

Examine the code below:


              123456789101112131415
            
numbers = [2, 11, 4, 11, 5]
i = -1
counter = 0

# Count all 11 in the list
# We are using len(numbers) - 1 to break the loop without being 'out of range'
while i < len(numbers) - 1:
  i = i + 1
  if numbers[i] != 11:
    continue
  else:
    print('11 is here!')
    counter += 1

print("Total number of '11': ", counter)

How does the code work?

Task

Halt the loop when encountering a negative value.

Initialize a while loop, employing i to interact with numbers.
Increment the value of i.
Display a message along with the negative element.
Employ break and continue as needed.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

Section 2. Chapter 5

Break/Continue in a while Loop

Now, we'll attempt the same task we previously accomplished with the for loop—finding a number in the list and terminating the loop once it's located.

Examine the code below:


              12345678910
            
numbers = [2, 3, 4, 11, 5]
i = 0

# Breaking the loop, if 11 is found
while i < len(numbers):
  if numbers[i] == 11:
    print('11 is here!')
    break
  else:
    i = i + 1

How does the code work?

Great!

Please be aware that the continue statement skips a block of code within the loop for the current iteration only. Now, let's count the occurrences of 11s in the code using continue.

Examine the code below:


              123456789101112131415
            
numbers = [2, 11, 4, 11, 5]
i = -1
counter = 0

# Count all 11 in the list
# We are using len(numbers) - 1 to break the loop without being 'out of range'
while i < len(numbers) - 1:
  i = i + 1
  if numbers[i] != 11:
    continue
  else:
    print('11 is here!')
    counter += 1

print("Total number of '11': ", counter)

How does the code work?

Task

Halt the loop when encountering a negative value.

Initialize a while loop, employing i to interact with numbers.
Increment the value of i.
Display a message along with the negative element.
Employ break and continue as needed.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

Now, we'll attempt the same task we previously accomplished with the for loop—finding a number in the list and terminating the loop once it's located.

Examine the code below:


              12345678910
            
numbers = [2, 3, 4, 11, 5]
i = 0

# Breaking the loop, if 11 is found
while i < len(numbers):
  if numbers[i] == 11:
    print('11 is here!')
    break
  else:
    i = i + 1

How does the code work?

Great!

Please be aware that the continue statement skips a block of code within the loop for the current iteration only. Now, let's count the occurrences of 11s in the code using continue.

Examine the code below:


              123456789101112131415
            
numbers = [2, 11, 4, 11, 5]
i = -1
counter = 0

# Count all 11 in the list
# We are using len(numbers) - 1 to break the loop without being 'out of range'
while i < len(numbers) - 1:
  i = i + 1
  if numbers[i] != 11:
    continue
  else:
    print('11 is here!')
    counter += 1

print("Total number of '11': ", counter)

How does the code work?

Task

Halt the loop when encountering a negative value.

Initialize a while loop, employing i to interact with numbers.
Increment the value of i.
Display a message along with the negative element.
Employ break and continue as needed.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Section 2. Chapter 5

Switch to desktop for real-world practiceContinue from where you are using one of the options below