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If/Else in a Nested Loop | Nested Loops
Python Loops Tutorial
course content

Course Content

Python Loops Tutorial

Python Loops Tutorial

1. The for Loop
2. The while Loop
3. Nested Loops

bookIf/Else in a Nested Loop

Utilizing if statements remains consistent whether applied within nested loops or in a single while or for loop.

Examine the code below:

123456789101112131415161718
matrix = [[1, -4, 4, 29], [3, 4, -200, -1], [10, -5, 0, 8]] # Changing negative numbers to 'N' i = 0 # Setting outer while loop to work with the number of rows while i < len(matrix): j = 0 # Setting inner while loop to work with the number of elements in the row while j < len(matrix[i]): if matrix[i][j] > 0: print(matrix[i][j], end = ' ') else: print('N', end = ' ') j +=1 i += 1 print('')
copy

How does the code work?

We've just observed an example of utilizing if/else within a nested loop while handling the matrix.

Now, in your assignment, you'll be dealing with two strings.

Feel free to refer to hints if necessary!

Task
test

Swipe to show code editor

Print all the vowels from the text.

  1. Initialize i.

  2. Configure the outer while loop to iterate through the number of elements in the text.

  3. Configure the inner for loop to iterate through the number of elements in the vowels.

  4. Implement the condition: if an element in the text matches one of the elements in vowels, then print the element.

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Section 3. Chapter 5
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bookIf/Else in a Nested Loop

Utilizing if statements remains consistent whether applied within nested loops or in a single while or for loop.

Examine the code below:

123456789101112131415161718
matrix = [[1, -4, 4, 29], [3, 4, -200, -1], [10, -5, 0, 8]] # Changing negative numbers to 'N' i = 0 # Setting outer while loop to work with the number of rows while i < len(matrix): j = 0 # Setting inner while loop to work with the number of elements in the row while j < len(matrix[i]): if matrix[i][j] > 0: print(matrix[i][j], end = ' ') else: print('N', end = ' ') j +=1 i += 1 print('')
copy

How does the code work?

We've just observed an example of utilizing if/else within a nested loop while handling the matrix.

Now, in your assignment, you'll be dealing with two strings.

Feel free to refer to hints if necessary!

Task
test

Swipe to show code editor

Print all the vowels from the text.

  1. Initialize i.

  2. Configure the outer while loop to iterate through the number of elements in the text.

  3. Configure the inner for loop to iterate through the number of elements in the vowels.

  4. Implement the condition: if an element in the text matches one of the elements in vowels, then print the element.

Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
Everything was clear?

How can we improve it?

Thanks for your feedback!

Section 3. Chapter 5
toggle bottom row

bookIf/Else in a Nested Loop

Utilizing if statements remains consistent whether applied within nested loops or in a single while or for loop.

Examine the code below:

123456789101112131415161718
matrix = [[1, -4, 4, 29], [3, 4, -200, -1], [10, -5, 0, 8]] # Changing negative numbers to 'N' i = 0 # Setting outer while loop to work with the number of rows while i < len(matrix): j = 0 # Setting inner while loop to work with the number of elements in the row while j < len(matrix[i]): if matrix[i][j] > 0: print(matrix[i][j], end = ' ') else: print('N', end = ' ') j +=1 i += 1 print('')
copy

How does the code work?

We've just observed an example of utilizing if/else within a nested loop while handling the matrix.

Now, in your assignment, you'll be dealing with two strings.

Feel free to refer to hints if necessary!

Task
test

Swipe to show code editor

Print all the vowels from the text.

  1. Initialize i.

  2. Configure the outer while loop to iterate through the number of elements in the text.

  3. Configure the inner for loop to iterate through the number of elements in the vowels.

  4. Implement the condition: if an element in the text matches one of the elements in vowels, then print the element.

Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
Everything was clear?

How can we improve it?

Thanks for your feedback!

Utilizing if statements remains consistent whether applied within nested loops or in a single while or for loop.

Examine the code below:

123456789101112131415161718
matrix = [[1, -4, 4, 29], [3, 4, -200, -1], [10, -5, 0, 8]] # Changing negative numbers to 'N' i = 0 # Setting outer while loop to work with the number of rows while i < len(matrix): j = 0 # Setting inner while loop to work with the number of elements in the row while j < len(matrix[i]): if matrix[i][j] > 0: print(matrix[i][j], end = ' ') else: print('N', end = ' ') j +=1 i += 1 print('')
copy

How does the code work?

We've just observed an example of utilizing if/else within a nested loop while handling the matrix.

Now, in your assignment, you'll be dealing with two strings.

Feel free to refer to hints if necessary!

Task
test

Swipe to show code editor

Print all the vowels from the text.

  1. Initialize i.

  2. Configure the outer while loop to iterate through the number of elements in the text.

  3. Configure the inner for loop to iterate through the number of elements in the vowels.

  4. Implement the condition: if an element in the text matches one of the elements in vowels, then print the element.

Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
Section 3. Chapter 5
Switch to desktopSwitch to desktop for real-world practiceContinue from where you are using one of the options below
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