Course Content

Python Loops Tutorial

Break/Continue in a Nested Loop

If the break statement is employed within a nested loop, it will terminate the innermost loop.

Examine the code below:


              12345678
            
# Not allowing the nested loop to work for j == 3 and i == 2
for i in range(4):
  if i == 2:
      break
  for j in range(4):
    if j == 3:
      break
    print(i, j)

How does the code work?

Please note that when the continue statement is encountered inside the loop, it skips all the statements below it and immediately moves to the next iteration.

Examine the code below:


              12345678910
            
numbers_1 = [1, 2, 3]
numbers_2 = [1, 2, 4]

# Printing the sum of number_1 and number_2 elements, ignoring the sum of the same elements
for i in numbers_1:
  for j in numbers_2:
    if i == j:
      continue
    else:
      print(i, '+', j, '= ', i + j)

How does the code work?

Task

You need to filter out symbols and numbers from the given list.

Configure the outer for loop to iterate through the number of rows in the matrix.
Configure the inner for loop to iterate through the elements in each row of the matrix.
Implement the following conditions: If an element is '#', then continue the loop; else if an element is '!', then break out of the loop; if an element is neither '#' nor '!', then print this element.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

Section 3. Chapter 6

Break/Continue in a Nested Loop

If the break statement is employed within a nested loop, it will terminate the innermost loop.

Examine the code below:


              12345678
            
# Not allowing the nested loop to work for j == 3 and i == 2
for i in range(4):
  if i == 2:
      break
  for j in range(4):
    if j == 3:
      break
    print(i, j)

How does the code work?

Please note that when the continue statement is encountered inside the loop, it skips all the statements below it and immediately moves to the next iteration.

Examine the code below:


              12345678910
            
numbers_1 = [1, 2, 3]
numbers_2 = [1, 2, 4]

# Printing the sum of number_1 and number_2 elements, ignoring the sum of the same elements
for i in numbers_1:
  for j in numbers_2:
    if i == j:
      continue
    else:
      print(i, '+', j, '= ', i + j)

How does the code work?

Task

You need to filter out symbols and numbers from the given list.

Configure the outer for loop to iterate through the number of rows in the matrix.
Configure the inner for loop to iterate through the elements in each row of the matrix.
Implement the following conditions: If an element is '#', then continue the loop; else if an element is '!', then break out of the loop; if an element is neither '#' nor '!', then print this element.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

Section 3. Chapter 6

Break/Continue in a Nested Loop

If the break statement is employed within a nested loop, it will terminate the innermost loop.

Examine the code below:


              12345678
            
# Not allowing the nested loop to work for j == 3 and i == 2
for i in range(4):
  if i == 2:
      break
  for j in range(4):
    if j == 3:
      break
    print(i, j)

How does the code work?

Please note that when the continue statement is encountered inside the loop, it skips all the statements below it and immediately moves to the next iteration.

Examine the code below:


              12345678910
            
numbers_1 = [1, 2, 3]
numbers_2 = [1, 2, 4]

# Printing the sum of number_1 and number_2 elements, ignoring the sum of the same elements
for i in numbers_1:
  for j in numbers_2:
    if i == j:
      continue
    else:
      print(i, '+', j, '= ', i + j)

How does the code work?

Task

You need to filter out symbols and numbers from the given list.

Configure the outer for loop to iterate through the number of rows in the matrix.
Configure the inner for loop to iterate through the elements in each row of the matrix.
Implement the following conditions: If an element is '#', then continue the loop; else if an element is '!', then break out of the loop; if an element is neither '#' nor '!', then print this element.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Thanks for your feedback!

If the break statement is employed within a nested loop, it will terminate the innermost loop.

Examine the code below:


              12345678
            
# Not allowing the nested loop to work for j == 3 and i == 2
for i in range(4):
  if i == 2:
      break
  for j in range(4):
    if j == 3:
      break
    print(i, j)

How does the code work?

Please note that when the continue statement is encountered inside the loop, it skips all the statements below it and immediately moves to the next iteration.

Examine the code below:


              12345678910
            
numbers_1 = [1, 2, 3]
numbers_2 = [1, 2, 4]

# Printing the sum of number_1 and number_2 elements, ignoring the sum of the same elements
for i in numbers_1:
  for j in numbers_2:
    if i == j:
      continue
    else:
      print(i, '+', j, '= ', i + j)

How does the code work?

Task

You need to filter out symbols and numbers from the given list.

Configure the outer for loop to iterate through the number of rows in the matrix.
Configure the inner for loop to iterate through the elements in each row of the matrix.
Implement the following conditions: If an element is '#', then continue the loop; else if an element is '!', then break out of the loop; if an element is neither '#' nor '!', then print this element.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Section 3. Chapter 6

Switch to desktop for real-world practiceContinue from where you are using one of the options below